Chapter 7: Problem 10
A physicist finds that an unknown radioactive substance registers 2000 counts per minute on a Geiger counter. Ten days later the substance registers 1500 counts per minute. Approximate its half-life.
Short Answer
Expert verified
The approximate half-life of the substance is 24.07 days.
Step by step solution
01
Understand the Exponential Decay Model
The problem of radioactive decay can be modeled by the exponential decay formula:\[ N(t) = N_0 e^{-kt} \]where \( N(t) \) is the amount remaining at time \( t \), \( N_0 \) is the initial amount, and \( k \) is the decay constant. We are given \( N_0 = 2000 \) and \( N(10) = 1500 \).
02
Set Up the Exponential Decay Equation
Using the given values in the exponential decay model, we have:\[ 1500 = 2000 \, e^{-10k} \]
03
Solve for the Decay Constant \( k \)
Divide both sides by 2000 to isolate the exponential term:\[ \frac{1500}{2000} = e^{-10k} \]\[ 0.75 = e^{-10k} \]Take the natural logarithm of both sides:\[ \ln(0.75) = -10k \]Solve for \( k \):\[ k = -\frac{\ln(0.75)}{10} \]
04
Calculate the Decay Constant \( k \)
Calculate \( k \) using the obtained expression:\[ k \approx -\frac{-0.287682}{10} \approx 0.0287682 \]
05
Find the Half-Life Formula
The half-life \( T_{1/2} \) is given by:\[ T_{1/2} = \frac{\ln(2)}{k} \]
06
Calculate the Half-Life
Substitute the value of \( k \) into the half-life formula:\[ T_{1/2} = \frac{\ln(2)}{0.0287682} \approx \frac{0.693147}{0.0287682} \approx 24.07 \text{ days} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Exponential Decay
Exponential decay is a mathematical process describing how quantities decrease over time. In our context, it refers to the decrease in the amount of a radioactive substance. When a substance decays exponentially, the amount remaining at any time can be expressed using the formula:
- \( N(t) = N_0 e^{-kt} \)
- \( N(t) \) is the amount of substance left after time \( t \).
- \( N_0 \) is the initial quantity of the substance.
- \( e \) is the base of natural logarithms, approximately equal to 2.71828.
- \( k \) is the decay constant.
Half-Life Calculation
The half-life of a radioactive substance is the time it takes for half of the substance to decay. This is a critical concept for understanding how long a substance will remain active. When viewing exponential decay, the half-life \( T_{1/2} \) can be found using:
- \( T_{1/2} = \frac{\ln(2)}{k} \)
Decay Constant
The decay constant \( k \) is a crucial factor in the exponential decay equation. It represents the probability of decay of a single atom per unit time. The decay constant directly impacts how fast or slow a radioactive substance will decay. To find \( k \), rearrange the exponential decay formula:
- \( 0.75 = e^{-10k} \)
- \( k = -\frac{\ln(0.75)}{10} \)