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Exer. \(3-4:\) The table lists point-masses (in kilograms) and their locations (in meters) in an \(x y\) -plane. Find \(m\), \(M_{x}, M_{y},\) and the center of mass of the system. $$ \begin{array}{|l|c|c|c|} \hline \text { mass } & 2 & 7 & 5 \\ \hline \text { location } & (4,-1) & (-2,0) & (-8,-5) \\ \hline \end{array} $$

Short Answer

Expert verified
Total mass \( m = 14 \), moments \( M_{x} = -46 \), \( M_{y} = -27 \), and center of mass at \((-1.929, -3.286)\).

Step by step solution

01

Calculate Total Mass (m)

To find the total mass \( m \), we sum up all the individual masses:\[ m = 2 + 7 + 5 = 14 \]
02

Calculate Moment about the Y-axis (Mx)

The moment about the \( y \)-axis, denoted as \( M_{x} \), is calculated using the formula \( M_{x} = \sum (m_i \cdot x_i) \):\[ M_{x} = 2(4) + 7(-2) + 5(-8) = 8 - 14 - 40 = -46 \]
03

Calculate Moment about the X-axis (My)

The moment about the \( x \)-axis, denoted as \( M_{y} \), is calculated using the formula \( M_{y} = \sum (m_i \cdot y_i) \):\[ M_{y} = 2(-1) + 7(0) + 5(-5) = -2 + 0 - 25 = -27 \]
04

Calculate x-coordinate of Center of Mass (x̄)

The \( x \)-coordinate of the center of mass \( \bar{x} \) is given by \( \bar{x} = \frac{M_{y}}{m} \):\[ \overline{x} = \frac{-27}{14} \approx -1.929 \]
05

Calculate y-coordinate of Center of Mass (ȳ)

The \( y \)-coordinate of the center of mass \( \bar{y} \) is given by \( \bar{y} = \frac{M_{x}}{m} \):\[ \overline{y} = \frac{-46}{14} \approx -3.286 \]
06

Determine Center of Mass

The center of mass \( (\bar{x}, \bar{y}) \) for the system is:\[ (\overline{x}, \overline{y}) = \left( -1.929, -3.286 \right) \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Point-Masses
Point-masses are individual masses considered to be concentrated at a single point in a space. In many physics and engineering problems, complex objects are simplified as point-masses to make calculations more manageable. Think of point-masses like individual dots on a grid, each representing a certain amount of weight at a specific location. In our exercise, we have three point-masses located on an XY plane:
  • Mass 1: 2 kg at the point (4, -1)
  • Mass 2: 7 kg at the point (-2, 0)
  • Mass 3: 5 kg at the point (-8, -5)
Each mass contributes both to the total mass of the system and to the moments about the axes. By having distinct positions, these point-masses influence the overall balance point or center of mass of the system. As you explore point-masses, imagine how each one's location and size affect where the entire system might balance on a single point.
Total Mass Calculation
Calculating the total mass of a system is one of the simplest but most essential steps to finding the center of mass. To determine the total mass, simply sum up the weights of all point-masses. This cumulative value helps us understand the entire system's mass without worrying about individual contributions afterward.

In our exercise, we have:
  • Mass 1: 2 kg
  • Mass 2: 7 kg
  • Mass 3: 5 kg
By adding these masses together, we find the total mass:
  • Total mass, \( m = 2 + 7 + 5 = 14 \) kg
This 14 kg represents the complete weight of the system, playing a crucial role in finding how this mass is distributed spatially through moments around axes.
Moment about the Y-axis
The moment about the y-axis, denoted as \( M_{x} \), measures how far, and with what mass, each point-mass is from the y-axis. To find this, multiply each mass by its x-coordinate and sum the results. This
  • Mass 1's moment: \( 2(4) = 8 \)
  • Mass 2's moment: \( 7(-2) = -14 \)
  • Mass 3's moment: \( 5(-8) = -40 \)
Add these up to get the total moment about the y-axis:
  • \( M_{x} = 8 - 14 - 40 = -46 \)
A negative moment indicates that the combined mass acts more strongly on one side of the y-axis. This affects the center of mass's x-coordinate, informing us how off-center the mass is distributed around the y-axis.
Moment about the X-axis
To understand how mass is distributed relative to the x-axis, we calculate the moment about this axis, denoted as \( M_{y} \). This involves multiplying each mass by its y-coordinate, indicating how the mass contributes to balancing around the x-axis.
  • Mass 1's moment: \( 2(-1) = -2 \)
  • Mass 2's moment: \( 7(0) = 0 \)
  • Mass 3's moment: \( 5(-5) = -25 \)
Summing these values gives us:
  • \( M_{y} = -2 + 0 - 25 = -27 \)
Similar to the moment about the y-axis, the negative value here signifies a tendency for the system's center of mass to lean more in the negative direction along the y-axis. Understanding these moments allows us to pinpoint the center of mass, revealing the system's balance point in a clear and precise manner.

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