Chapter 5: Problem 9
Evaluate the integral. $$ \int_{4}^{9} \frac{t-3}{\sqrt{t}} d t $$
Short Answer
Expert verified
The value of the integral is \( \frac{20}{3} \).
Step by step solution
01
Rewrite the Integrand
First, simplify the expression \( \frac{t-3}{\sqrt{t}} \) by writing \( t-3 \) as \( \frac{t}{\sqrt{t}} - \frac{3}{\sqrt{t}} \). This can be rewritten as \( t^{1/2} - 3t^{-1/2} \). Now, our integral becomes \( \int_{4}^{9} (t^{1/2} - 3t^{-1/2}) \, dt \).
02
Integrate Term by Term
The integral \( \int_{4}^{9} (t^{1/2} - 3t^{-1/2}) \, dt \) can be split into two separate integrals: \( \int_{4}^{9} t^{1/2} \, dt \) and \(-3\int_{4}^{9} t^{-1/2} \, dt \). We'll integrate each term separately.
03
Integrate \( t^{1/2} \)
To integrate \( t^{1/2} \), use the power rule: \( \int t^{n} \, dt = \frac{t^{n+1}}{n+1} + C \). Here, \( n = \frac{1}{2} \), so \( \int t^{1/2} \, dt = \frac{t^{3/2}}{3/2} = \frac{2}{3}t^{3/2} \). Evaluate this from 4 to 9 to get \( \left[ \frac{2}{3}t^{3/2} \right]_{4}^{9} = \frac{2}{3}(9^{3/2} - 4^{3/2}) \).
04
Integrate \( -3t^{-1/2} \)
For \(-3\int t^{-1/2} \, dt\), the power rule gives \( \int t^{-1/2} \, dt = \frac{t^{1/2}}{1/2} = 2t^{1/2} \). This gives us \( -3(2t^{1/2}) = -6t^{1/2} \). Evaluate from 4 to 9 to get \( \left[ -6t^{1/2} \right]_{4}^{9} = -6(9^{1/2} - 4^{1/2}) \ = -6(3 - 2) \ = -6 \).
05
Combine Results
Summing the results from Steps 3 and 4, we have \( \frac{2}{3}(9^{3/2} - 4^{3/2}) - 6 \). Calculate \( 9^{3/2} = 27 \) and \( 4^{3/2} = 8 \), so the first part is \( \frac{2}{3}(27 - 8) = \frac{2}{3} \times 19 = \frac{38}{3} \). Include the contribution from the second integral, \(-6\), leading to \( \frac{38}{3} - 6 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Power Rule for Integration
The Power Rule for Integration is a fundamental concept that simplifies taking integrals of functions in the form of a power of a variable. If you have a function of the form \( t^n \), where \( n \) is any real number except -1, the Power Rule states:
- \( \int t^n \, dt = \frac{t^{n+1}}{n+1} + C \)
Evaluating Definite Integrals
Evaluating definite integrals involves both finding the antiderivative of a function and then evaluating it at the given limits of integration. For example, to evaluate \( \int_{4}^{9} t^{1/2} \, dt \) from 4 to 9:
- First, find the antiderivative using the Power Rule: \( \frac{2}{3}t^{3/2} \).
- Then, apply the limits: calculate \( \left[ \frac{2}{3}t^{3/2} \right]_{4}^{9} \), which results in \( \frac{2}{3}(9^{3/2} - 4^{3/2}) \).
Simplifying Integrands
Simplifying an integrand is a crucial initial step when working with definite integrals as it often reduces a complex expression into a more manageable form. In our original exercise, the expression \( \frac{t-3}{\sqrt{t}} \) can be initially intimidating, but by using algebraic manipulation, we can rewrite it:
- Express \( \frac{t}{\sqrt{t}} - \frac{3}{\sqrt{t}} \) as \( t^{1/2} - 3t^{-1/2} \).