Chapter 5: Problem 5
Evaluate. $$ \int\left(\frac{1}{z^{3}}-\frac{3}{z^{2}}\right) d z $$
Short Answer
Expert verified
The integral evaluates to \(-\frac{1}{2z^2} + \frac{3}{z} + C\).
Step by step solution
01
Break Down the Integral
The given integral can be separated into two separate integrals. Rewrite the problem as: \[ \int \frac{1}{z^3} \, dz - \int \frac{3}{z^2} \, dz. \]
02
Simplify Each Term
Change each term to have a negative exponent to simplify the integration process:\[\int z^{-3} \, dz - 3 \int z^{-2} \, dz.\]
03
Integrate Each Term
Apply the power rule for integration, which states \( \int z^n \, dz = \frac{z^{n+1}}{n+1} + C \), where \( C \) is a constant. - For \( \int z^{-3} \, dz \): \[ \frac{z^{-2}}{-2} = -\frac{1}{2}z^{-2}. \]- For \( -3 \int z^{-2} \, dz \): \[ -3 \left(\frac{z^{-1}}{-1}\right) = 3z^{-1}. \]
04
Combine the Results
Combine the results of the integrals from step 3:\[-\frac{1}{2}z^{-2} + 3z^{-1} + C.\]
05
Re-cast the Expression
Re-cast \( z^{-2} \) and \( z^{-1} \) back to fractions:\[-\frac{1}{2z^2} + \frac{3}{z} + C.\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Power Rule for Integration
The power rule for integration is a fundamental concept in calculus that greatly simplifies the process of finding antiderivatives. It states that if you have a function of the form \( z^n \), where \( n eq -1 \), its integral is given by:\[\int z^n \, dz = \frac{z^{n+1}}{n+1} + C,\]where \( C \) represents the constant of integration. This rule allows us to handle a wide variety of polynomial functions easily.To apply the power rule:
- Identify the exponent \( n \) of the term.
- Add 1 to \( n \) to get \( n+1 \).
- Divide the term \( z^{n+1} \) by \( n+1 \).
Definite Integral
A definite integral is a type of integral that calculates the area under a curve between two specified limits. Unlike indefinite integrals, which include a constant \( C \), definite integrals result in a specific numerical value. The format for a definite integral is:\[\int_{a}^{b} f(z) \, dz,\]where \( a \) and \( b \) are the lower and upper limits of integration, respectively.To evaluate a definite integral:
- Find the antiderivative of the function \( f(z) \).
- Substitute the upper limit \( b \) into the antiderivative to find \( F(b) \).
- Substitute the lower limit \( a \) into the antiderivative to find \( F(a) \).
- Subtract \( F(a) \) from \( F(b) \) to get the final area value.
Integral of Negative Exponents
When dealing with integrals of negative exponents, first transform the terms to a form where the power rule can be easily applied. For example, for terms like \( \frac{1}{z^n} \), write them as \( z^{-n} \). This makes the integration process straightforward since you will then use the power rule:\[\int z^{-n} \, dz = \frac{z^{-n+1}}{-n+1} + C.\]Here's how to integrate each term:
- Convert division expressions into negative exponents.
- Apply the power rule for integration to each term.
- If necessary, simplify the expression to return to positive exponents or fractions.