Chapter 5: Problem 11
Approximate the definite integral for the stated value of \(n\) by using (a) the trapezoidal rule and (b) Simpson's rule. (Approximate each \(f\left(x_{k}\right)\) to four decimal places, and round off answers to two decimal places, whenever appropriate.) \(\int_{0}^{\pi} \sqrt{\sin x} d x ; \quad n=6\)
Short Answer
Step by step solution
Divide the Interval
Calculate Points for Subintervals
Evaluate Function at Subintervals
Apply Trapezoidal Rule
Apply Simpson's Rule
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Trapezoidal Rule
Here is how it works. First, divide the interval of integration into smaller, equally spaced subintervals. Calculate the width of each subinterval using \( \Delta x = \frac{b-a}{n} \), where \( b \) and \( a \) are the limits of integration, and \( n \) is the number of subintervals.
For the function \( f(x) \), the Trapezoidal Rule estimates the integral as:
\[ T = \frac{\Delta x}{2} \left[ f(x_0) + 2 \sum_{k=1}^{n-1} f(x_k) + f(x_n) \right] \]
In this exercise, the interval \([0, \pi]\) is divided into 6 subintervals, and trapezoidal approximations lead to a solution of approximately 1.54.
Simpson's Rule
A requirement for Simpson's Rule is that the number of subintervals, \( n \), must be even. Much like the Trapezoidal Rule, you divide the integration range into equal parts, but the actual formula is slightly different:
\[ S = \frac{\Delta x}{3} \left[ f(x_0) + 4 \sum_{k=1, \text{odd}}^{n-1} f(x_k) + 2 \sum_{k=2, \text{even}}^{n-2} f(x_k) + f(x_n) \right] \]
What happens here is that every second term of the sample points is weighted more heavily with a coefficient of 4, reflecting Simpson's parabolic approximation.
For simulating this exercise with \( n=6 \), the process evaluates to about 1.57, providing a slightly more accurate integration compared to the Trapezoidal Rule.
Definite Integral Approximation
The idea is to replace the continuous curve with a set of simpler geometric shapes (like rectangles, trapezoids, or parabolic arcs), for which the area can be more easily calculated. The integration process then consists of summing the areas of these shapes to get an approximation of the "real" integral.
Numerical integration techniques are important in fields like physics and engineering, where they help solve real-world problems where exact solutions are difficult to obtain. Though approximate, these methods provide insight with controlled accuracy by using chosen subdivisions (like \( n = 6 \) in this case). Despite their limitations, they bring practical solutions to real problems.