Chapter 3: Problem 40
The formula \(T=2 \pi \sqrt{l g}\) relates the length \(l\) of a pendulum to its period \(T,\) where \(g\) is a gravitational constant. What percentage change in the length corresponds to a \(30 \%\) increase in the period?
Short Answer
Expert verified
A 30% increase in period results in a 69% increase in length.
Step by step solution
01
Understand the Formula
The formula we are working with is \( T = 2 \pi \sqrt{\frac{l}{g}} \). This formula relates the period \( T \) of a pendulum to its length \( l \), with \( g \) being a constant. Our goal is to find how changes in \( T \) affect \( l \).
02
Rearrange for Length
To express the length in terms of the period, rearrange the formula: \[ T = 2\pi \sqrt{\frac{l}{g}} \implies \sqrt{\frac{l}{g}} = \frac{T}{2\pi} \implies \frac{l}{g} = \left(\frac{T}{2\pi}\right)^2 \implies l = g\left(\frac{T}{2\pi}\right)^2 \].
03
Calculate New Period
If the period \( T \) increases by 30%, the new period \( T' \) is \( T' = 1.3T \).
04
Calculate New Length Expression
Using the new period \( T' \), substitute into the length equation: \[ l' = g \left( \frac{1.3T}{2\pi} \right)^2 = g \cdot \left(\frac{1.3}{2\pi}\right)^2 T^2 \].
05
Compare Initial and New Lengths
Since \( l = g \cdot \left(\frac{1}{2\pi}\right)^2 T^2 \), comparing \( l' \) to \( l \), the ratio \( \frac{l'}{l} = \left(1.3\right)^2 = 1.69 \) implies a 69% increase in length.
06
Calculate Percentage Change in Length
The length change percentage \( \Delta l \) is \( 69\% \) because the new length is 1.69 times the original, translating to a 69% increase.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Gravitational Constant
The gravitational constant, commonly denoted as \( g \), plays a crucial role in pendulum motion. It represents the acceleration due to gravity acting on objects near Earth's surface. Typically, \( g \) is approximately \( 9.81 \, \text{m/s}^2 \). In the context of a pendulum, this constant helps determine how fast the pendulum swings back and forth.
Understanding this constant is important because it influences the period \( T \) of a pendulum. A higher gravitational constant would mean a shorter period, as the pendulum would swing faster under greater gravitational pull. Conversely, a lower \( g \) would extend the period.
The gravitational constant helps to standardize calculations of pendulum behavior, allowing us to make predictions about the period based on varying lengths \( l \). Without it, comparing pendulum behavior across different environmental conditions would be difficult, since \( g \) can vary slightly with elevation and geographical location.
Understanding this constant is important because it influences the period \( T \) of a pendulum. A higher gravitational constant would mean a shorter period, as the pendulum would swing faster under greater gravitational pull. Conversely, a lower \( g \) would extend the period.
The gravitational constant helps to standardize calculations of pendulum behavior, allowing us to make predictions about the period based on varying lengths \( l \). Without it, comparing pendulum behavior across different environmental conditions would be difficult, since \( g \) can vary slightly with elevation and geographical location.
Percentage Change
Percentage change is a useful concept for understanding how alterations in one variable affect another proportionally. In the pendulum scenario, we're interested in how a change in period \( T \) affects the pendulum's length \( l \).
To express a percentage change, you compare the difference between the new and the original value, then divide by the original value, and multiply by 100 to convert to a percentage. For example, a 30% increase in \( T \) implies \( T' = 1.3T \).
Calculating the corresponding change in length \( l \) involves following the same process. Using the relationship established earlier, if the new length is 1.69 times the initial length, the percentage increase in length is \( 69\% \). This tells us that for a 30% increase in the period, the length of the pendulum increases by 69%.
To express a percentage change, you compare the difference between the new and the original value, then divide by the original value, and multiply by 100 to convert to a percentage. For example, a 30% increase in \( T \) implies \( T' = 1.3T \).
Calculating the corresponding change in length \( l \) involves following the same process. Using the relationship established earlier, if the new length is 1.69 times the initial length, the percentage increase in length is \( 69\% \). This tells us that for a 30% increase in the period, the length of the pendulum increases by 69%.
Length and Period Relationship
The relationship between length \( l \) and period \( T \) of a pendulum is crucial for understanding pendulum dynamics. According to the formula \( T = 2 \pi \sqrt{\frac{l}{g}} \), the period \( T \) is directly related to the square root of the length \( l \).
This means that as \( l \) increases, \( T \) also increases, but not linearly. Instead, it follows a square root relationship; doubling the length of the pendulum, for instance, would result in a period that is roughly \( \sqrt{2} \) or about 1.41 times longer.
When tackling problems like the one presented, where an increase in the period by 30% results in an increased length, it's this non-linear square root function that explains the larger-than-expected increase in length. This relationship demonstrates why small changes in period can lead to significant changes in length.
This means that as \( l \) increases, \( T \) also increases, but not linearly. Instead, it follows a square root relationship; doubling the length of the pendulum, for instance, would result in a period that is roughly \( \sqrt{2} \) or about 1.41 times longer.
When tackling problems like the one presented, where an increase in the period by 30% results in an increased length, it's this non-linear square root function that explains the larger-than-expected increase in length. This relationship demonstrates why small changes in period can lead to significant changes in length.