Chapter 3: Problem 25
Find the derivative. $$ g(w)=\frac{w^{2}-4 w+3}{w^{3 / 2}} $$
Short Answer
Expert verified
The derivative is \( g'(w) = \frac{1}{2}w^{-1/2} + 2w^{-3/2} - \frac{9}{2}w^{-5/2} \).
Step by step solution
01
Simplify the Function
Start by expressing the given function in a form that is easier to differentiate. Rewrite the function as: \[ g(w) = w^{2} \cdot w^{-3/2} - 4w \cdot w^{-3/2} + 3 \cdot w^{-3/2} \] Simplify each term: \[ g(w) = w^{2 - 3/2} - 4w^{1 - 3/2} + 3w^{-3/2} \] This simplifies to: \[ g(w) = w^{1/2} - 4w^{-1/2} + 3w^{-3/2} \].
02
Differentiate Each Term Separately
Use the power rule \( \frac{d}{dw}[w^n] = n \cdot w^{n-1} \) to differentiate each term. For \( w^{1/2} \): \[ \frac{d}{dw}(w^{1/2}) = \frac{1}{2}w^{-1/2} \] For \( -4w^{-1/2} \): \[ \frac{d}{dw}(-4w^{-1/2}) = -4 \cdot \left( -\frac{1}{2} \right)w^{-3/2} = 2w^{-3/2} \] For \( 3w^{-3/2} \): \[ \frac{d}{dw}(3w^{-3/2}) = 3 \cdot \left( -\frac{3}{2} \right)w^{-5/2} = -\frac{9}{2}w^{-5/2} \].
03
Combine the Derivative Terms
Now combine the derivatives of each term to form the derivative of the entire function:\[ g'(w) = \frac{1}{2}w^{-1/2} + 2w^{-3/2} - \frac{9}{2}w^{-5/2} \].
04
Write Final Simplified Derivative
The final simplified derivative of the function \( g(w) \) is:\[ g'(w) = \frac{1}{2}w^{-1/2} + 2w^{-3/2} - \frac{9}{2}w^{-5/2} \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Power Rule
The power rule is a fundamental tool in calculus, especially useful in differentiation. It is commonly used to take derivatives of functions of the form \( x^n \), where \( n \) is any real number. The power rule formula states that the derivative of \( x^n \) is \( nx^{n-1} \). This simple rule helps quickly find derivatives without needing complex calculations.
For example, if we have \( w^{1/2} \), applying the power rule gives us \( \frac{1}{2}w^{-1/2} \). Similarly, for any term like \( -4w^{-1/2} \), the derivative is calculated using the power rule, resulting in \( 2w^{-3/2} \).
For example, if we have \( w^{1/2} \), applying the power rule gives us \( \frac{1}{2}w^{-1/2} \). Similarly, for any term like \( -4w^{-1/2} \), the derivative is calculated using the power rule, resulting in \( 2w^{-3/2} \).
- Key Points of the Power Rule:
- Fast and efficient for polynomial expressions.
- Applicable to functions with any real exponent.
The Art of Simplification
Simplification in calculus is often necessary to prepare a function for differentiation. Before applying rules like the power rule, it's essential to make the function easier to manage.
In the given problem, the function \( g(w) = \frac{w^{2}-4w+3}{w^{3/2}} \) is initially complex. We begin by rewriting it in a form that separates each term with the same base but different exponents:
In the given problem, the function \( g(w) = \frac{w^{2}-4w+3}{w^{3/2}} \) is initially complex. We begin by rewriting it in a form that separates each term with the same base but different exponents:
- Apply basic algebra to express each term with \( w^{n} \) format, such as \( w^{2-3/2} - 4w^{1-3/2} + 3w^{-3/2} \).
Differentiation in Practice
Differentiation is the process of finding a derivative, which shows how a function changes at any given point. This concept is crucial for understanding the behavior of curves and is widely used in science and engineering.
Once a function is simplified, as shown in the problem with \( g(w) = w^{1/2} - 4w^{-1/2} + 3w^{-3/2} \), we differentiate each term independently:
Once a function is simplified, as shown in the problem with \( g(w) = w^{1/2} - 4w^{-1/2} + 3w^{-3/2} \), we differentiate each term independently:
- Use the power rule to compute derivatives term by term.
- Combine the results to get the overall derivative.
Functions and Their Behavior
Functions are mathematical relationships between different variables, typically represented as \( f(x) \). Understanding a function's behavior involves knowing how it changes, which is where derivatives are essential.
In the example provided, the function \( g(w) \) describes a ratio involving polynomial terms. Functions like this are analyzed by finding derivatives that tell us how the function's value changes.
In the example provided, the function \( g(w) \) describes a ratio involving polynomial terms. Functions like this are analyzed by finding derivatives that tell us how the function's value changes.
- Different types of functions (linear, polynomial, rational) require distinct approaches to simplification and differentiation.
- Analyzing derivatives helps in predicting and understanding the function's dynamics.