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Let \(x\) denote a measurement with a maximum error of \(\Delta x\). Use differentials to approximate the average error and the percentage error for the calculated value of \(y .\) $$ y=6 \sqrt[3]{x} ; \quad x=8, \quad \Delta x=\pm 0.03 $$

Short Answer

Expert verified
Average error: ±0.015; Percentage error: ≈ 0.125%.

Step by step solution

01

Define the Differentials Formula

To find the average error using differentials, we start with the formula for the differential of a function. Here, since the function is given by \(y = 6\sqrt[3]{x}\), the differential \(dy\) can be written as \(dy = f'(x) \cdot dx\).
02

Find the Derivative

We need the derivative of \(y = 6\sqrt[3]{x}\) with respect to \(x\). The derivative is \( y' = 6 \times \frac{1}{3} x^{-2/3} = 2x^{-2/3} \).
03

Evaluate the Derivative at Given \(x\)

Substitute \(x = 8\) into the derivative \(y' = 2x^{-2/3}\) to find \(y'(8) = 2 \times 8^{-2/3}\). Simplifying gives us \(y'(8) = \frac{1}{2}\).
04

Calculate the Differential

The differential \(dy\) can be calculated using \(dy = y'(8) \cdot \Delta x\). With \(y'(8) = \frac{1}{2}\) and \(\Delta x = \pm 0.03\), we find \(dy = \frac{1}{2} \times 0.03 = \pm 0.015\).
05

Calculate the Percentage Error

To find the percentage error, divide the differential \(|dy|\) by the value of \(y\) when \(x=8\). First, calculate \(y\) at \(x=8\), which is \(y = 6\sqrt[3]{8} = 6 \times 2 = 12\). Thus, the percentage error is \(\frac{|dy|}{y} \times 100\% = \frac{0.015}{12} \times 100\% \).
06

Final Computation

Calculate \(\frac{0.015}{12} \times 100\%\). This gives \(\approx 0.125\%\). Therefore, the percentage error is approximately \(0.125\%\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Error Approximation
Error approximation is a technique used to estimate the range of values within which the true value of a function might lie due to small errors in measurement, typically denoted as \( \Delta x \). This technique is particularly valuable in situations where we can't precisely determine a function's value because of the limitations of measurement tools.

In many cases, differencing methods involving differentials are employed. The differential \( dy \) approximates how much \( y \), the function's output, changes as \( x \), the input, changes by a small amount \( dx \). This leads to the main concept, the differential formula:
  • \( dy = f'(x) \cdot dx \)
Here, \( f'(x) \) is the derivative of the function, measuring the rate of change in \( y \) with respect to \( x \). Understanding error approximation can help us maintain a high degree of accuracy in real-world calculations despite potential errors.
Percentage Error
Percentage error is a metric that helps to comprehend how significant an error is in relation to the true measurement itself. It is an expression of the absolute error as a percentage of the true value, enabling one to gauge the relative significance of the error.

To calculate the percentage error in this context, follow these steps:
  • Determine the differential \( |dy| \), which reflects the estimated absolute error resulting from \( \Delta x \).
  • Compute the actual value of \( y \) at a particular point, as in \( y = 6\sqrt[3]{8} = 12 \).
  • The percentage error is obtained by the formula \( \text{Percentage Error} = \frac{|dy|}{y} \times 100\% \).
This percentage reflects how the small allowable error in \( x \) translates into an error in \( y \). It's crucial for assessing the reliability of our calculations in practical applications. In the example given, even a tiny error in measurement translates to a small \(0.125\%\) error in interpretation, revealing how precise measurement influences accuracy.
Derivative Calculation
Calculating the derivative is a fundamental step needed for both error approximation and percentage error evaluations. The derivative of a function describes the sensitivity of the function to changes in the input; essentially outlining how quickly \( y \) will change as \( x \) is altered.

To compute the derivative for the function \( y = 6\sqrt[3]{x} \), we apply differentiation rules:
  • The power rule and constant multiplication result in \( y' = 6 \times \frac{1}{3}x^{-2/3} \).
  • This simplifies to \( y' = 2x^{-2/3} \).

Substituting the specific value \( x = 8 \) into the derivative formula gives \( y'(8) = 2 \times 8^{-2/3} = \frac{1}{2} \). The derivative value is then used to find the differential \( dy \) by multiplying by \( \Delta x \). Therefore, derivative calculations not only help understand the behavior of a function but also are pivotal in estimating how measurements impact function outputs.

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