Chapter 18: Problem 17
Find the flux of \(F\) over the closed surface S. (Use the outer normal to S.) \(\mathbf{F}(x, y, z)=(x+y) \mathbf{i}+z \mathbf{j}+x z \mathbf{k}\) \(S\) is the surface of the cube having vertices \((\pm 1,\pm 1,\pm 1) .\)
Short Answer
Expert verified
The flux of \( \mathbf{F} \) over the cube is 12.
Step by step solution
01
Define the Divergence Theorem
According to the Divergence Theorem, the flux of a vector field \( \mathbf{F} \) through a closed surface \( S \) is equal to the volume integral of the divergence of \( \mathbf{F} \) over the volume \( V \) enclosed by \( S \). The theorem is given by: \[ \Phi = \int\int\int_V abla \cdot \mathbf{F} \, dV \] where \( \Phi \) represents the total flux over the surface.
02
Compute the Divergence of \( \mathbf{F} \)
To apply the Divergence Theorem, first calculate the divergence \( abla \cdot \mathbf{F} \) of the vector field \( \mathbf{F}(x, y, z) = (x+y) \mathbf{i} + z \mathbf{j} + xz \mathbf{k} \):\[ abla \cdot \mathbf{F} = \frac{\partial}{\partial x}(x+y) + \frac{\partial}{\partial y}z + \frac{\partial}{\partial z}(xz) \]Carrying out the partial derivatives gives:\[ abla \cdot \mathbf{F} = 1 + 0 + x = 1 + x \] which is the divergence of \( \mathbf{F} \).
03
Set Up the Volume Integral
Define the region of integration. The cube extends from \(-1\) to \(1\) along each axis. We thus integrate over the volume from \(x = -1\) to \(1\), \(y = -1\) to \(1\), and \(z = -1\) to \(1\) using the calculated divergence:\[ \int_{-1}^{1} \int_{-1}^{1} \int_{-1}^{1} (1+x) \, dz \, dy \, dx \]
04
Evaluate the Integral Step-by-Step
Calculate the integral with respect to \( z \):\[ \int_{-1}^{1} (1+x) \ dz = (1+x)(z) \bigg|_{-1}^{1} = (1+x)[1 - (-1)] = 2(1+x) \]Then integrate with respect to \( y \):\[ \int_{-1}^{1} 2(1+x) \, dy = 2(1+x)(y) \bigg|_{-1}^{1} = 2(1+x)[1 - (-1)] = 4(1+x) \]Finally, integrate with respect to \( x \):\[ \int_{-1}^{1} 4(1+x) \, dx = 4 \left[ x + \frac{x^2}{2} \right]_{-1}^{1} = 4 \left[ (1 + \frac{1}{2}) - (-1 + \frac{1}{2}) \right] \]\[ = 4 \left[ \frac{3}{2} + \frac{3}{2} \right] = 4 \times 3 = 12 \]
05
Conclude the Calculation
The result of the volume integral is \( 12 \). Therefore, the flux of \( \mathbf{F} \) over the closed surface \( S \) of the cube is \( 12 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Fields
A vector field assigns a vector to every point in space. These vectors can vary in magnitude and direction across different points. A common notation for vector fields is \( \mathbf{F}(x, y, z) \), where the components are usually functions of the spatial coordinates \( x, y, z \). In this exercise, the vector field is defined as \( \mathbf{F}(x, y, z) = (x+y) \mathbf{i} + z \mathbf{j} + xz \mathbf{k} \).The components of this vector field determine how vectors are distributed across a space. Here:
- The \( \mathbf{i} \) component \((x+y)\) suggests that the vector varies not only on the \( x \) component but also depends on the \( y \) position.
- The \( \mathbf{j} \) component is simply \( z \), meaning its influence linearly grows with the \( z \) coordinate.
- Lastly, the \( \mathbf{k} \) component, \( xz \), multiplies \( x \) with \( z \), indicating this component increases more rapidly in areas where both \( x \) or \( z \) are significant.
Flux Calculation
Flux calculation measures how much of the vector field passes through a surface. Imagine a surface in the vector field, like a mesh, and consider how much of the wind (as a vector field) flows through it. Flux can be simplified by using the Divergence Theorem.
The Divergence Theorem relates surface flux to a volume integral. It states that the total outflow of the vector field through a closed surface \(S\) can be determined by integrating the divergence over the volume \(V\) inside the surface:\[ \Phi = \int\int\int_V abla \cdot \mathbf{F} \, dV \]
In the current problem, after calculating the divergence \(abla \cdot \mathbf{F} = 1 + x\), it guides how flux is distributed within the enclosed volume of the surface.
The Divergence Theorem relates surface flux to a volume integral. It states that the total outflow of the vector field through a closed surface \(S\) can be determined by integrating the divergence over the volume \(V\) inside the surface:\[ \Phi = \int\int\int_V abla \cdot \mathbf{F} \, dV \]
In the current problem, after calculating the divergence \(abla \cdot \mathbf{F} = 1 + x\), it guides how flux is distributed within the enclosed volume of the surface.
Cubic Volume Integral
The integral over a cubic volume involves evaluating an expression within the boundaries of a cube. Here, the cube extends from \(-1\) to \(1\) along each of the \( x, y, z \) axes. These boundaries make sure that each side of the cube is touching a face of the cube defined by these values.
To compute this, we perform successive integrations of the divergence \(1+x\):
To compute this, we perform successive integrations of the divergence \(1+x\):
- First, integrate with respect to \( z \), which captures all values from the bottom to the top face of the cube.
- Next, integrate the resulting expression in relation to \( y \), spanning from one vertical face to the opposite one.
- Finally, integrate with respect to \( x \), moving from the front to the back face.