Chapter 18: Problem 11
Use Green's theorem to evaluate the line integral. \(\oint_{C}\left(x^{2}+y^{2}\right) d x+2 x y d y\) \(C\) is the boundary of the region bounded by the graphs of \(y=\sqrt{x}, y=0,\) and \(x=4\)
Short Answer
Expert verified
The line integral evaluates to 0.
Step by step solution
01
Identify the vector field and compute curl
Given the line integral \(\oint_{C}(x^2 + y^2) \, dx + 2xy \, dy\), we can identify the vector field \(\vec{F} = (P, Q) = (x^2 + y^2, 2xy)\). According to Green's Theorem, we need to find the curl which is \( \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \).Calculate \(\frac{\partial Q}{\partial x} = 2y\) and \(\frac{\partial P}{\partial y} = 2y\). Therefore, the curl is \(2y - 2y = 0\).
02
Establish the region of integration
The region \(D\) is bounded by \(y = \sqrt{x}\), \(y = 0\), and \(x = 4\). This is a region in the first quadrant that starts from \(x = 0\) to \(x = 4\), with the upper boundary being the curve \(y = \sqrt{x}\).
03
Apply Green's Theorem
Green's Theorem states \(\oint_{C} P \, dx + Q \, dy = \iint_{D} \left( \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right) dA \). From Step 1, we found the curl to be \(0\). Therefore, the double integral over the region \(D\) of the curl of \(\vec{F}\) is \(0\), making the line integral \(\oint_{C} (x^2 + y^2) \, dx + 2xy \, dy = \iint_{D} 0 \, dA = 0\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Line Integral
A line integral is a type of integral where functions are evaluated along a curve. It extends the concept of integrals beyond just the real line to curves in the plane or space. In simple terms, it accumulates all the little values along a path to find a total. These pathways can be straight, curved, or twisted – whatever suits our evaluation needs. In this context, the line integral is given by the expression \[\oint_{C} (x^2 + y^2) \, dx + 2xy \, dy\] which sums up changes along the curve \( C \). This often represents some physical quantities, like work done by a force field when an object moves along \( C \). It’s crucial to know that line integrals depend on both the path and the vector field they traverse.
Vector Field
A vector field is a top-notch representation of how vectors are applied in a particular space. Imagine you're in a world of invisible arrows indicating direction and magnitude at every single point in the plane or space. In the exercise, our vector field is represented as \[\vec{F} = (P, Q) = (x^2 + y^2, 2xy)\] Here, each point \((x, y)\) in the plane has an associated vector \( (x^2 + y^2, 2xy) \). Vector fields frequently appear in physics to show forces like gravity or electromagnetism. Just like weather maps illustrate wind speed and direction, vector fields offer a glimpse into how forces operate in a particular area.
Curl
The curl of a vector field gives us insight into how much and in which direction the vector field rotates around a point. It's derived from some nifty calculus, particularly partial derivatives. The formula to find the curl is:\[\frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y}\]In simpler terms, if the curl is high, the vector field tends to spiral around that point. Conversely, a zero curl implies there's no rotation happening; it's as calm as a still river. In our case, the curl of \[(x^2 + y^2, 2xy)\] is zero, meaning no swirls or rotations within the region. This result simplifies the double integral application in Green's Theorem, revealing that the line integral evaluates to zero as well.
Double Integral
A double integral goes the next step in integration by handling functions of two variables over regions in the plane. Think of it as taking an assortment of tiny pieces under a surface and adding them together to discover the total volume or area. Within the context of Green's Theorem, we use the double integral \[\iint_{D} \, 0 \, dA\]over the region \( D \) to calculate the total of the curl.
- The double integral examines every little section of the area \( D \) bounded by the graphs of \( y = \sqrt{x}, y = 0, \) and \( x = 4 \).
- The result of a double integral can provide insights into collective quantities such as area, charge, or even mass when density is considered.