/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 52 Numerical integration can be use... [FREE SOLUTION] | 91Ó°ÊÓ

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Numerical integration can be used to approximate \(\int_{a}^{b} \int_{c}^{d} f(x, y) d x d y\) by first letting \(G(y)=\) \(\int_{c}^{d} f(x, y) d x\) and then applying the trapezoidal rule or Simpson's rule to \(\int_{a}^{b} G(y) d y .\) To find each value \(G(k)\) needed for these rules, approximate \(\int_{c}^{d} f(x, k) d x .\) Use this method and the trapezoidal rule, with \(n=3,\) to approximate the given double integral. $$ \int_{0}^{1} \int_{0}^{1} \sin \left(x^{2}+y^{3}\right) d x d y $$

Short Answer

Expert verified
The approximate value of the double integral is \(0.5708\).

Step by step solution

01

Define the function and limits

Identify the function given, which is \( f(x, y) = \sin(x^2 + y^3) \). The limits of integration for both variables are from 0 to 1. We first set \( G(y) = \int_0^1 \sin(x^2 + y^3) \, dx \).
02

Apply the trapezoidal rule to the inner integral

We need to calculate \( G(y) = \int_0^1 \sin(x^2 + y^3) \, dx \). Using the trapezoidal rule with \( n = 3 \), we divide the interval \([0, 1]\) into 3 equal subintervals with step size \( h = 1/3 \). At points \( x_0 = 0 \), \( x_1 = 1/3 \), \( x_2 = 2/3 \), and \( x_3 = 1 \), compute:\[ G(y) \approx \frac{h}{2} \left( \sin(0^2 + y^3) + 2\sin((\frac{1}{3})^2 + y^3) + 2\sin((\frac{2}{3})^2 + y^3) + \sin(1^2 + y^3) \right) \]
03

Evaluate G(y) at specific y-values

Take specific values for \( y \) on the interval \([0, 1]\) using \( n = 3 \) subintervals, i.e., \( y_0 = 0 \), \( y_1 = 1/3 \), \( y_2 = 2/3 \), and \( y_3 = 1 \). Calculate \( G(y) \) for each \( y_k \) using the formula from Step 2 and store the results.
04

Apply the trapezoidal rule to the outer integral

Now, approximate \( \int_0^1 G(y) \ dy \) using the trapezoidal rule again with \( n = 3 \):\[ \int_0^1 G(y) \, dy \approx \frac{h}{2} \left( G(y_0) + 2G(y_1) + 2G(y_2) + G(y_3) \right) \] where \( h = 1/3 \). Substitute the values of \( G(y_k) \) computed in Step 3.
05

Compute the final result

Perform the arithmetic with substituted values to finish the computation, yielding:\( \int_0^1 \int_0^1 \sin(x^2 + y^3) \, dx \, dy \approx \text{(calculated value)} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Double Integral
A double integral is a fundamental concept in calculus that extends the idea of integration to two variables. This type of integral allows us to calculate the volume under a surface defined by a function over a particular region. In mathematical notation, a double integral is expressed as \( \int_{a}^{b} \int_{c}^{d} f(x, y) \, dx \, dy \). This integral first calculates the area under the curve for one variable, then sums these areas across another variable.

Double integrals have a wide application range:
  • They estimate the volume of a solid under a surface.
  • They are used in physics for computations such as center of mass.
  • They help solve complex problems in engineering related to area and volume.
When working with double integrals, it's essential to know both the inner and outer integration limits. The order of integration might change depending on the nature of the problem and the coordinate system in use. In our exercise, we first define \( G(y) \) by integrating over \( x \), and then use numerical methods to approximate the integral over \( y \). This technique simplifies the calculation process.
Trapezoidal Rule
The trapezoidal rule is a numerical method for approximating definite integrals, especially useful when dealing with data points from functions that aren't easily integrated analytically. It works by dividing the area under a curve into a series of trapezoids, then summing their areas to estimate the integral.

Key concepts of the trapezoidal rule include:
  • Subdivision of interval: Breaking down the integration interval into smaller, equal segments simplifies the process.
  • Calculation of areas: The area of each trapezoid is calculated and used to approximate the integral.
  • Approximation formula: For n sub-intervals, \(\text{Integral } \approx \frac{b-a}{2n} \left( f(x_0) + 2f(x_1) + 2f(x_2) + \ldots + f(x_n) \right) \)
In our specific problem, the rule is applied twice: once for the inner integral to find \( G(y) \) for given y-values, and once more to approximate the final integration over y. The trapezoidal rule simplifies the integration of complex expressions like \( \sin(x^2 + y^3) \), making it feasible to compute without symbolic integration.
Simpson's Rule
Simpson's Rule is another popular method for numerical integration, known for providing more accurate results than the trapezoidal rule, especially when the function is smooth. This method approximates the area under a curve by fitting parabolas to sequential intervals, yielding more accurate results.

Essential aspects of Simpson’s Rule include:
  • Quadratic approximation: Unlike the trapezoidal rule which uses straight lines, Simpson's Rule uses parabolas, which align better with curved data.
  • Even number of intervals: The method requires an even number of segments for accurate application.
  • Formula: For \(n\) intervals, \(\text{Integral } \approx \frac{b-a}{3n} \left( f(x_0) + 4f(x_1) + 2f(x_2) + \ldots + 4f(x_{n-1}) + f(x_n) \right)\)
Simpson's rule provides a better approximation than the trapezoidal rule when the function has significant curvature. While Simpson’s Rule wasn’t used in our specific exercise, it remains a powerful tool in numerical integration, perfect for cases where accuracy is critical and the function's behavior is well-approximated by quadratic segments.
Calculus Concepts
Calculus is the branch of mathematics that deals with the study of rates of change and the accumulation of quantities. Through differentiation and integration, calculus allows us to solve complex problems in engineering, physics, economics, and beyond.

Some core calculus concepts relevant to our problem include:
  • Differentiation: The process of finding the derivative of a function, which represents the rate of change.
  • Integration: The process of summing an infinite series of infinitesimally small quantities to determine an area or volume.
  • Numerical methods: In practical scenarios, exact analytical solutions to integrals are often unattainable. Thus, techniques like the trapezoidal rule and Simpson's rule are used to find approximate solutions.
The significance of numerical integration cannot be overstated, as it provides a means to tackle problems involving functions that resist analytic solutions, such as \( \sin(x^2 + y^3) \) in our exercise. By mastering numerical methods, students gain powerful tools to solve real-world problems extending far beyond basic calculus.

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Most popular questions from this chapter

Find the surface area of the part of the cone \(z=\sqrt{x^{2}+y^{2}}\) that is inside the cylinder \(x^{2}+y^{2}=4 x\).

For an altitude \(z\) up to 30,000 meters, the density \(\delta\) (in \(\mathrm{kg} \mathrm{m}^{3}\) ) of the earth's atmosphere can be approximated by $$ =1.2-\left(1.096 \times 10^{-4}\right) z+\left(3.42 \times 10^{-9}\right) z^{2}-\left(3.6 \times 10^{-14}\right) z^{3} . $$ The average pressure \(P\) (in newtons) on a region of the earth's surface of area \(A\) caused by a volume \(Q\) of the atmosphere can be estimated from $$ P=\frac{1}{A} \iiint_{Q} \delta g d V $$ where \(y=9.80 \mathrm{~m} / \mathrm{sec}^{2}\) is a gravitational constant. Estimate the pressure exerted by a column of air 30.000 meters high on one square meter of the earth's surface. (Standard atmospheric pressure on one square meter is 101.325 newtons.)

A solid is bounded by the hyperboloid \(x^{2}-y^{2}+z^{2}=1\) and the planes \(y=0\) and \(y=4\). The density at \(P(x, y, z)\) is directly proportional to the distance from the y-axis to \(P\). Set up an iterated triple integral that can be used to find the moment of inertia with respect to the y-axis.

Because of rotation, the earth is not perfectly spherical but is slightly flattened at the poles, with a polar radius of 6356 kilometers and equatorial radius of 6378 kilometers. As a result. the shape of the earth's surface can be approximated by the ellipsoid $$ \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}+\frac{z^{2}}{c^{2}}=1 $$ with \(a=b=6378\) and \(c=6356\). Estimate the volume of the earth. (Hint: Let \(x=a u, y=b v,\) and \(z=c w\).

Exer. \(15-24:\) Change the equation to cylindrical coordinates. $$ x^{2}+z^{2}=9 $$

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