Chapter 17: Problem 37
Exer. \(37-38:\) Let \(T\) be the indicated transformation from the ur-plane to the \(x y\) -plane. Graph the points \((u, v)\) such that \(\hat{c}(x, y) / \partial(u, v)=0\) for the indicated values of \(u\). (This graph shows where \(T\) is not one-toone.) \(x=\frac{1}{4} v^{4}+u^{2}, \quad y=u-\cos v:-\pi \leq u \leq \pi\)
Short Answer
Step by step solution
Define the Problem
Calculate Partial Derivatives
Compute the Jacobian Determinant
Solve for Zero Jacobian
Analyze Solutions
Graph Points Where T is Not One-to-One
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Jacobian Matrix
For our problem, the Jacobian matrix is a 2x2 matrix that looks like this:
- First row: \(\frac{\partial x}{\partial u}, \frac{\partial x}{\partial v}\)
- Second row: \(\frac{\partial y}{\partial u}, \frac{\partial y}{\partial v}\)
Partial Derivatives
In the exercise, for example, to calculate \(\frac{\partial x}{\partial u}\), you consider changes in \(x\) as \(u\) changes, while \(v\) remains fixed. This results in a formula that captures the local rate of change:
- \(\frac{\partial x}{\partial u} = 2u\)
- \(\frac{\partial x}{\partial v} = v^3\)
- \(\frac{\partial y}{\partial u} = 1\)
- \(\frac{\partial y}{\partial v} = \sin v\)
One-to-One Transformation
Checking for one-to-oneness involves finding where the Jacobian determinant equals zero. When this happens, it signifies critical points where the transformation possibly loses its one-to-one property.
For the given transformation, the deterrent to being one-to-one is at points where:
- \(2u \sin v = v^3\)
Graphing Transformations
From our solutions, graphing involves plotting all points \(u, v\) satisfying the conditions:
- Vertical line at \(u=0\), extending from \(-\pi \leq v \leq \pi\)
- Horizontal lines at \(v=0\) and other integer multiples of \(\pi\) within the range for \(u\)