Chapter 15: Problem 24
The general helix is a curve whose tangent vector makes a constant angle with a fixed unit vector \(\mathbf{u}\). Show that the curve with parametrization \(x=3 t-t^{3}, y=3 t^{2}\), \(z=3 t+t^{3} ; t\) in \(\mathbb{R}\) is a general helix by finding an appropriate vector \(\mathbf{u}\).
Short Answer
Expert verified
The curve is a general helix with the unit vector \( \mathbf{u} = \left( \frac{1}{\sqrt{2}}, 0, \frac{1}{\sqrt{2}} \right) \).
Step by step solution
01
Calculate the Tangent Vector of the Curve
Given curve parametrization is \( \mathbf{r}(t) = (3t - t^3, 3t^2, 3t + t^3) \). To find the tangent vector \( \mathbf{T}(t) \), compute the derivative of \( \mathbf{r}(t) \) with respect to \( t \):\[ \mathbf{T}(t) = \frac{d\mathbf{r}}{dt} = \left( \frac{d}{dt}(3t - t^3), \frac{d}{dt}(3t^2), \frac{d}{dt}(3t + t^3) \right) = (3 - 3t^2, 6t, 3 + 3t^2). \]
02
Determine the Fixed Unit Vector \(\mathbf{u}\)
A general helix satisfies that the tangent vector \( \mathbf{T}(t) \) makes a constant angle with a fixed vector \( \mathbf{u} \). Assume \( \mathbf{u} = (a, b, c) \). The dot product \( \mathbf{T}(t) \cdot \mathbf{u} = (3 - 3t^2)a + 6tb + (3 + 3t^2)c \) should be constant. To satisfy this condition, note that terms involving \( t \) must cancel out or combine to form a constant. Choosing \( a = c \) and \( b = 0 \) yields: \[ \mathbf{T}(t) \cdot \mathbf{u} = (3a + 3c), \] which is constant.
03
Ensure \(\mathbf{u}\) is a Unit Vector
Since \( \mathbf{u} = (a, 0, a) \), enforce the unit norm condition: \( \| \mathbf{u} \| = 1 \). Thus \( \sqrt{a^2 + 0 + a^2} = \sqrt{2a^2} = \sqrt{2}|a| = 1 \). Solving gives \( |a| = \frac{1}{\sqrt{2}} \). Therefore, \( \mathbf{u} \) can be \( \left( \frac{1}{\sqrt{2}}, 0, \frac{1}{\sqrt{2}} \right) \) or \( \left( -\frac{1}{\sqrt{2}}, 0, -\frac{1}{\sqrt{2}} \right) \).
04
Conclusion and Final Verification
Substituting \( \mathbf{u} = \left( \frac{1}{\sqrt{2}}, 0, \frac{1}{\sqrt{2}} \right) \) into \( \mathbf{T}(t) \cdot \mathbf{u} \) confirms constant value \( 3 \sqrt{2} \), thus satisfying the helix condition where the tangent makes a constant angle with \( \mathbf{u} \). This concludes that the curve is indeed a general helix.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parametric Equations
Parametric equations are a fundamental tool in calculus used to represent curves, functions, and surfaces. Instead of describing a curve as a direct relation between two variables like \( x \) and \( y \), parametric equations introduce a third variable, often denoted as \( t \), known as a parameter.
For example, in a 3D space, a curve can be defined by equations like \( x(t) = 3t - t^3 \), \( y(t) = 3t^2 \), and \( z(t) = 3t + t^3 \). Here, as \( t \) varies, you trace a path in the 3D space, efficiently describing complex curves such as helices or spirals.
For example, in a 3D space, a curve can be defined by equations like \( x(t) = 3t - t^3 \), \( y(t) = 3t^2 \), and \( z(t) = 3t + t^3 \). Here, as \( t \) varies, you trace a path in the 3D space, efficiently describing complex curves such as helices or spirals.
- Advantages include visualizing motion and dynamically altering shapes by changing the parameter \( t \).
- They enable a straightforward calculation of tangents, areas, and volumes.
Tangent Vector
The tangent vector is a critical concept when dealing with parametric equations and 3D geometry. It provides valuable information about the velocity and direction of a curve at any given point.
To find the tangent vector to a curve parameterized by \( \mathbf{r}(t) = (x(t), y(t), z(t)) \), calculate the derivative \( \mathbf{T}(t) = \frac{d\mathbf{r}}{dt} \).
In our exercise, the tangent vector of the curve \( \mathbf{r}(t) = (3t - t^3, 3t^2, 3t + t^3) \) is computed as \( \mathbf{T}(t) = (3 - 3t^2, 6t, 3 + 3t^2) \). This derivative vector reveals both the direction in which the curve is heading and its speed.
To find the tangent vector to a curve parameterized by \( \mathbf{r}(t) = (x(t), y(t), z(t)) \), calculate the derivative \( \mathbf{T}(t) = \frac{d\mathbf{r}}{dt} \).
In our exercise, the tangent vector of the curve \( \mathbf{r}(t) = (3t - t^3, 3t^2, 3t + t^3) \) is computed as \( \mathbf{T}(t) = (3 - 3t^2, 6t, 3 + 3t^2) \). This derivative vector reveals both the direction in which the curve is heading and its speed.
- The calculation of \( \mathbf{T}(t) \) helps in understanding essential properties of the curve, such as points of inflection and curvature.
- It provides a linear approximation of the curve near a point, which is foundational in calculus.
Dot Product
The dot product is a versatile algebraic operation on two vectors that yields a scalar. It is fundamental for understanding angles and projections in vector spaces.
In mathematical terms, the dot product of vectors \( \mathbf{a} = (a_1, a_2, a_3) \) and \( \mathbf{b} = (b_1, b_2, b_3) \) is given by \( \mathbf{a} \cdot \mathbf{b} = a_1b_1 + a_2b_2 + a_3b_3 \). This product is crucial for determining when two vectors are perpendicular, when their dot product equals zero.
In the context of a general helix, the dot product \( \mathbf{T}(t) \cdot \mathbf{u} \) ensures that the tangent vector maintains a constant angle with a fixed unit vector.
In mathematical terms, the dot product of vectors \( \mathbf{a} = (a_1, a_2, a_3) \) and \( \mathbf{b} = (b_1, b_2, b_3) \) is given by \( \mathbf{a} \cdot \mathbf{b} = a_1b_1 + a_2b_2 + a_3b_3 \). This product is crucial for determining when two vectors are perpendicular, when their dot product equals zero.
In the context of a general helix, the dot product \( \mathbf{T}(t) \cdot \mathbf{u} \) ensures that the tangent vector maintains a constant angle with a fixed unit vector.
- It allows the decomposition of vectors into components parallel and perpendicular to a given direction.
- The dot product is used in physics to calculate work done when a force is applied over a distance.
Unit Vector
A unit vector is a vector with a magnitude or norm equal to one. They are essential in vector mathematics since they provide the direction of vectors without concern for magnitude.
To ensure a vector \( \mathbf{v} = (v_1, v_2, v_3) \) is a unit vector, its norm \( \| \mathbf{v} \| \) must equal one: \( \sqrt{v_1^2 + v_2^2 + v_3^2} = 1 \).
In the problem of the helix, finding a suitable unit vector \( \mathbf{u} \) involved satisfying this condition, leading to the solution \( \mathbf{u} = \left( \frac{1}{\sqrt{2}}, 0, \frac{1}{\sqrt{2}} \right) \) or its negative counterpart.
To ensure a vector \( \mathbf{v} = (v_1, v_2, v_3) \) is a unit vector, its norm \( \| \mathbf{v} \| \) must equal one: \( \sqrt{v_1^2 + v_2^2 + v_3^2} = 1 \).
In the problem of the helix, finding a suitable unit vector \( \mathbf{u} \) involved satisfying this condition, leading to the solution \( \mathbf{u} = \left( \frac{1}{\sqrt{2}}, 0, \frac{1}{\sqrt{2}} \right) \) or its negative counterpart.
- Unit vectors serve as basis vectors in coordinate systems, helping to simplify vector calculations.
- They are powerful tools in projecting one vector along the direction of another, especially in physics and engineering.