Chapter 14: Problem 6
Find parametric equations for the line through \(P_{1}\) and \(P_{2}\). Determine (if possible) the points at which the line intersects each of the coordinate planes. $$ P_{1}(-3,1,-1), \quad P_{2}(7,11,-8) $$
Short Answer
Expert verified
The line has parametric equations \(x = -3 + 10t\), \(y = 1 + 10t\), \(z = -1 - 7t\), and intersects the coordinate planes at \([-\frac{31}{7}, \frac{3}{7}, 0]\), \([-4, 0, -\frac{3}{10}]\), \([0, 4, -\frac{31}{10}]\).
Step by step solution
01
Find the Direction Vector
First, determine the direction vector of the line by subtracting the coordinates of \(P_1\) from \(P_2\). This gives us \(\langle 7 - (-3), 11 - 1, -8 - (-1) \rangle = \langle 10, 10, -7 \rangle\).
02
Write Parametric Equations for the Line
Using point \(P_1(-3, 1, -1)\) and the direction vector \(\langle 10, 10, -7 \rangle\), write the parametric equations as follows:- \(x = -3 + 10t\)- \(y = 1 + 10t\)- \(z = -1 - 7t\) where \(t\) is a parameter.
03
Find Intersection with the XY-Plane
Set \(z = 0\) in the parametric equations to find the intersection with the XY-plane. From \(-1 - 7t = 0\), solve for \(t\) to get \(t = -\frac{1}{7}\). Substitute \(t = -\frac{1}{7}\) into \(x = -3 + 10t\) and \(y = 1 + 10t\) to find the intersection point \(\left(-\frac{31}{7}, \frac{3}{7}, 0\right)\).
04
Find Intersection with the XZ-Plane
Set \(y = 0\) in the parametric equations to find the intersection with the XZ-plane. From \(1 + 10t = 0\), solve for \(t = -\frac{1}{10}\). Substitute \(t = -\frac{1}{10}\) into \(x = -3 + 10t\) and \(z = -1 - 7t\) to get the intersection point \(\left(-4, 0, -\frac{3}{10}\right)\).
05
Find Intersection with the YZ-Plane
Set \(x = 0\) in the parametric equations to find the intersection with the YZ-plane. From \(-3 + 10t = 0\), solve for \(t = \frac{3}{10}\). Substitute \(t = \frac{3}{10}\) into \(y = 1 + 10t\) and \(z = -1 - 7t\) to find the intersection point \(\left(0, 4, -\frac{31}{10}\right)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Direction Vector
The direction vector is a fundamental concept in understanding the orientation and trajectory of a line in space. When you are working with parametric equations of lines, the direction vector helps to define in which direction the line extends. For a line passing through two points, the direction vector can be found by subtracting the coordinates of one point from the other. For example, given two points, \(P_{1}(-3,1,-1)\) and \(P_{2}(7,11,-8)\), the direction vector \(\mathbf{d}\) is determined as follows:
- Subtract the x-coordinates: \(7 - (-3) = 10\)
- Subtract the y-coordinates: \(11 - 1 = 10\)
- Subtract the z-coordinates: \(-8 - (-1) = -7\)
Intersection with Planes
The intersection of a line with a plane is where the line "cuts through" the plane. In three dimensions, we often explore intersections with the coordinate planes: XY-plane, XZ-plane, and YZ-plane. Each of these planes corresponds to setting one of the coordinates to zero. To find where a line intersects these planes, parametric equations can be used to substitute and solve:
- **XY-plane intersection:** Set \(z = 0\). Solve \(-1 - 7t = 0\) to find \(t = -\frac{1}{7}\). Insert this \(t\) in x and y parametric equations to locate the intersection.
- **XZ-plane intersection:** Set \(y = 0\). Solve \(1 + 10t = 0\) to find \(t = -\frac{1}{10}\). Use this in equations for \(x\) and \(z\) to determine the intersection point.
- **YZ-plane intersection:** Set \(x = 0\). Solve \(-3 + 10t = 0\) for \(t = \frac{3}{10}\). Substitute back into y and z equations to find this intersection.
Coordinate Geometry
Coordinate geometry, or analytic geometry, is the study of geometry using a coordinate system. This allows us to represent geometric figures using numbers and algebra. In three-dimensional space, points are represented as \( (x, y, z) \), which gives each point a unique position based on three numbers.This concept is powerful:
- Enables easy calculation of geometric properties like distance and angles.
- Allows visualization of how shapes, lines, and planes interact.
- Facilitates finding intersections and relationships between geometric entities.
Parametric Form
The parametric form of equations is a dynamic way to express lines using a parameter \(t\). Instead of expressing the line as a static equation, parametric equations describe the position of a point on the line based on the value of \(t\). The general format of a parametric equation for a line through a point \(P_1(x_1, y_1, z_1)\) with a direction vector \langle a, b, c \rangle\ is given by:
- \( x = x_1 + at \)
- \( y = y_1 + bt \)
- \( z = z_1 + ct \)
- \( x = -3 + 10t \)
- \( y = 1 + 10t \)
- \( z = -1 - 7t \)