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Exer. \(39-50:\) Sketch the graph of the equation. $$ x^{2}+y^{2}+z^{2}-14 x+6 y-8 z+10=0 $$

Short Answer

Expert verified
The graph is a sphere centered at (7, -3, 4) with radius 8.

Step by step solution

01

Identify the Type of Surface

The given equation is of the form \(x^2 + y^2 + z^2 + Ax + By + Cz + D = 0\). This indicates the equation of a sphere in 3D space.
02

Rearrange Equation

The original equation is \(x^2 + y^2 + z^2 - 14x + 6y - 8z + 10 = 0\). Rearrange by moving the constant to one side: \(x^2 - 14x + y^2 + 6y + z^2 - 8z = -10\).
03

Complete the Square for Each Variable

Complete the square for each variable:- For \(x\): \(x^2 - 14x\) becomes \((x-7)^2 - 49\)- For \(y\): \(y^2 + 6y\) becomes \((y+3)^2 - 9\)- For \(z\): \(z^2 - 8z\) becomes \((z-4)^2 - 16\)
04

Substitute Completed Squares into Equation

Replace the completed squares back into the equation:\((x-7)^2 - 49 + (y+3)^2 - 9 + (z-4)^2 - 16 = -10\)
05

Simplify the Equation

Add the constants on the left-hand side and simplify:\((x-7)^2 + (y+3)^2 + (z-4)^2 = 64\). This is the equation of a sphere with center \((7, -3, 4)\) and radius \(8\), since \(64 = 8^2\).
06

Sketch the Sphere

To sketch the sphere:- Draw a 3D coordinate system.- Plot the center at \((7, -3, 4)\).- Draw a sphere with radius \(8\) centered at this point. Ensure to depict the symmetry in all directions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equation of a Sphere
In three-dimensional geometry, a sphere is a set of points that are all the same distance from a fixed point, known as the center. This distance is called the radius. The general equation of a sphere in three-dimensional space is given by \[(x - h)^2 + (y - k)^2 + (z - l)^2 = r^2\] where - \((h, k, l)\) represent the coordinates of the center of the sphere, - \(r\) is the radius of the sphere.In the problem's original form, we had the equation \(x^2 + y^2 + z^2 - 14x + 6y - 8z + 10 = 0\).To convert this to the standard equation of a sphere, we completed the square for each variable, revealing the sphere's center and radius.
Completing the Square
Completing the square is a mathematical technique used to transform a quadratic expression into a perfect square trinomial. This method is essential for converting the general equation of a circle or sphere into its standard form. In the given problem, the equation had terms like \(x^2 - 14x\), \(y^2 + 6y\),and \(z^2 - 8z\).To complete the square:- For \(x\), find half of \(-14\) (which is \(-7\)) and square it to get \(49\). This makes \(x^2 - 14x\) into \((x-7)^2 - 49\).- For \(y\), half of \(6\) is \(3\), and squaring gives \(9\), so \(y^2 + 6y\) becomes \((y+3)^2 - 9\).- For \(z\), half of \(-8\) is \(-4\), and squaring yields \(16\). Hence, \(z^2 - 8z\) turns into \((z-4)^2 - 16\).These adjustments allow us to simplify and rearrange the equation into a more recognizable form.
Graphing 3D Surfaces
Graphing in three-dimensional space can be a challenging but rewarding task, especially when it involves shapes like spheres. To graph a sphere from its equation, it is essential to first identify the center and radius from the standard form equation.For the sphere determined by our exercise:- Identify the center at \((7, -3, 4)\),- Recognize the radius \(8\), since \(64 = 8^2\).Once these elements are known, you can proceed with sketching:
  • Begin by drawing a three-dimensional coordinate system.
  • Plot the center of the sphere at the identified coordinates.
  • Use the radius to determine the size of the sphere, ensuring symmetry in all directions from the center.
By carefully analyzing and plotting each element, creating a clear and accurate representation of a sphere in three-dimensional space becomes attainable.

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