Chapter 11: Problem 4
(a) Find the Maclaurin polynomials \(P_{1}(x)\), \(P_{2}(x),\) and \(P_{3}(x)\) for \(f(x) .\) (b) Sketch the graphs of \(P_{1}\) \(P_{2}, P_{3},\) and \(f\) on the same coordinate plane. (c) Approximate \(f(a)\) to four decimal places by means of \(P_{3}(a),\) and use \(R_{3}(a)\) to estimate the error in this approximation. $$ f(x)=\tan ^{-1} x ; \quad a=0.1 $$
Short Answer
Step by step solution
Calculate the derivatives of f(x)
Evaluate derivatives at x = 0
Write the Maclaurin polynomials P1(x), P2(x), P3(x)
Sketch the graphs of P1(x), P2(x), P3(x), and f(x)
Approximate f(a) using P3(a)
Estimate the error using R3(a)
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Derivatives Calculation
- The first derivative \( f'(x) \) represents the slope of the tangent line of the function at any point \( x \). We find that \( f'(x) = \frac{1}{1+x^2} \).
- The second derivative, \( f''(x) = -\frac{2x}{(1+x^2)^2} \), gives us information about the concavity of the function—if it's bending upwards or downwards.
- The third derivative, \( f'''(x) = \frac{2(3x^2-1)}{(1+x^2)^3} \), provides even more detail about the rate of change of the concavity.
Polynomial Approximation
- \( P_1(x) = x \) is a linear approximation. It captures only the initial slope of the function near \( x = 0 \).
- \( P_2(x) = x \) remains the same as \( P_1(x) \), because the second derivative yields a zero coefficient at \( x = 0 \).
- \( P_3(x) = x - \frac{1}{3}x^3 \) includes the cubic term, giving us a better approximation by considering the function's curvature around the origin.
Error Estimation
Inverse Trigonometric Functions
- \( \tan^{-1}(x) \) gives the angle whose tangent is \( x \).
- This function's behavior is crucial in creating accurate models in various scientific domains, often appearing in integration problems and when determining angle measures.
- Its derivatives help in understanding how the function changes at different points, crucial for creating Maclaurin polynomials that approximate the function near specific points like \( x = 0 \).