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Determine whether the series converges or diverges. \(\sum_{n=1}^{\infty} n \tan \frac{1}{n}\)

Short Answer

Expert verified
The series diverges.

Step by step solution

01

Analyze the Behavior of Terms for Large n

As a preliminary step, examine the behavior of the general term \( a_n = n \tan\frac{1}{n} \) for large \( n \). Use the approximation \( \tan x \approx x \) for small \( x \). Therefore, \( \tan\frac{1}{n} \approx \frac{1}{n} \), and thus \( a_n \approx n \cdot \frac{1}{n} = 1 \).
02

Consider the Limit Comparison Test

To use the Limit Comparison Test, choose a series with known convergence behavior to compare. Use the series \( \sum_{n=1}^{\infty} 1 \), which is the harmonic series and is known to diverge.
03

Apply the Limit Comparison Test

Compute the limit \( \lim_{n \to \infty} \frac{a_n}{b_n} \), where \( a_n = n \tan\frac{1}{n} \) and \( b_n = 1 \). We have \( \lim_{n \to \infty} \frac{n \tan\frac{1}{n}}{1} = \lim_{n \to \infty} n \tan\frac{1}{n} = 1 \), since we previously approximated \( n \tan\frac{1}{n} \approx 1 \).
04

Conclusion Based on Limit Comparison

Since the limit of \( \frac{a_n}{b_n} \) as \( n \) approaches infinity is a finite non-zero number (in this case, 1), the series \( \sum_{n=1}^{\infty} a_n \) has the same convergence behavior as \( \sum_{n=1}^{\infty} b_n \). Because the harmonic series \( \sum_{n=1}^{\infty} 1 \) diverges, the given series \( \sum_{n=1}^{\infty} n \tan\frac{1}{n} \) also diverges.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limit Comparison Test
When dealing with series convergence, the Limit Comparison Test is an incredibly useful tool. It allows us to determine whether a series converges or diverges by comparing it to another series with known behavior. The main idea is to compute the limit of the ratio of the terms of the two series as the index goes to infinity.

In mathematical terms, for two series \( \sum a_n \) and \( \sum b_n \), the Limit Comparison Test involves evaluating \( \lim_{n \to \infty} \frac{a_n}{b_n} \).
  • If this limit results in a finite non-zero number, both series either converge or diverge together.
  • If the limit is zero or infinity, the test is inconclusive, and another method should be used.

In our example, we compared the series \( \sum_{n=1}^{\infty} n \tan \frac{1}{n} \) with the harmonic series \( \sum_{n=1}^{\infty} 1 \). Since the limit of their term ratio is 1, this implies they share the same convergence behavior. As the harmonic series is known to diverge, our series also diverges.
Behavior of Series Terms
Understanding the behavior of a series' terms is fundamental to analyzing its convergence or divergence. This involves looking at how the terms behave as the index \( n \) grows larger.

For small values of a variable, well-known approximations can be applied to functions such as trigonometric, exponential, and logarithmic. In this scenario, we used the approximation \( \tan x \approx x \) when \( x \) is near zero. Therefore, for large \( n \), \( \tan \frac{1}{n} \approx \frac{1}{n} \).

As a result, the original terms of the series \( a_n = n \tan \frac{1}{n} \) simplify to \( a_n \approx 1 \) for large \( n \). This simplification not only makes calculations more manageable but also provides insights into choosing a comparison series, which is crucial for applying convergence tests.

Recognizing such patterns and behaviors of terms helps in easily determining the nature of complex series.
Harmonic Series Divergence
The harmonic series is a classic example in mathematics that demonstrates divergence. It is represented by the series \( \sum_{n=1}^{\infty} \frac{1}{n} \). Despite each term getting smaller, the series does not converge.

The divergence of the harmonic series can be proven using the integral test or by comparison with a similar integral. The fundamental idea is that the sum of the harmonic series grows without bound as more terms are added, regardless of the decreasing size of individual terms.

Many students find it counterintuitive that a series with diminishing terms may not converge. That's why it's a vital reference model in convergence analysis.

In the discussed example, the harmonic series serves as the baseline for comparison when applying the Limit Comparison Test. Its known divergence strengthens the conclusion that our series \( \sum_{n=1}^{\infty} n \tan \frac{1}{n} \) also diverges.
  • This presents a clear illustration of how an understanding of standard series behaviors can directly influence the analysis of more complex series.

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Most popular questions from this chapter

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