Chapter 11: Problem 28
Find Maclaurin's formula with remainder for the given \(f(x)\) and \(n\). $$ f(x)=e^{-x^{2}}, \quad n=3 $$
Short Answer
Expert verified
The Maclaurin series for \(f(x) = e^{-x^2}\) is \(1 - x^2\) with the remainder \(\frac{(12 - 48c^2 + 16c^4)e^{-c^2}x^4}{24}\).
Step by step solution
01
Understanding Maclaurin's Series
Maclaurin's series is a special case of Taylor's series around zero, given by:\[f(x) = f(0) + f'(0)x + \frac{f''(0)x^2}{2!} + \cdots + \frac{f^{(n)}(0)x^n}{n!} + R_n(x)\]where \(R_n(x)\) is the remainder term. For this exercise, we need to find the series for \(f(x) = e^{-x^2}\) up to \(n = 3\).
02
Calculate the Function's Derivatives
Calculate the first few derivatives of \(f(x) = e^{-x^2}\) and evaluate them at \(x = 0\). - \(f(x) = e^{-x^2}\)- \(f'(x) = -2xe^{-x^2}, \ f'(0) = 0\)- \(f''(x) = (-2+4x^2)e^{-x^2}, \ f''(0) = -2\)- \(f'''(x) = (8x-8x^3)e^{-x^2}, \ f'''(0) = 0\)
03
Construct the Maclaurin Polynomial
Use the derivatives calculated at \(x = 0\) to construct the Maclaurin polynomial:\[P_3(x) = f(0) + f'(0)x + \frac{f''(0)x^2}{2!} + \frac{f^{(3)}(0)x^3}{3!}\]Substitute the values:\[P_3(x) = 1 - \frac{2x^2}{2} = 1 - x^2\]
04
Determine the Remainder Term
The remainder term for the Maclaurin series is given by:\[R_3(x) = \frac{f^{(4)}(c)x^4}{4!}\]Find \(f^{(4)}(x)\) and substitute to find the remainder in terms of \(c\), where \(c\) is between 0 and \(x\). Substitute values:- \(f^{(4)}(x) = (12 - 48x^2 + 16x^4)e^{-x^2}\)Thus\[R_3(x) = \frac{f^{(4)}(c)x^4}{4!} = \frac{(12 - 48c^2 + 16c^4)e^{-c^2}x^4}{24}\]
05
Write the Complete Maclaurin Series with Remainder
Combining \(P_3(x)\) and \(R_3(x)\), the Maclaurin series with remainder for \(f(x) = e^{-x^2}\) is:\[f(x) = 1 - x^2 + \frac{(12 - 48c^2 + 16c^4)e^{-c^2}x^4}{24}\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Taylor Series
A Taylor series is a fascinating mathematical tool that expresses a function as an infinite sum of terms, calculated from the values of its derivatives at a single point. It provides a way to approximate complex functions using polynomials, which are much simpler to handle. For any function \( f(x) \), you can express it in the form of a Taylor series centered at a point \( a \) as follows:\[ f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)(x-a)^2}{2!} + \cdots + \frac{f^{(n)}(a)(x-a)^n}{n!} + R_n(x) \]
- \( f(a) \) is the value of the function at the point \( a \).
- \( f'(a), f''(a), \ldots \) are its derivatives at \( a \).
- \( n! \) is the factorial of \( n \), which is the product of all positive integers up to \( n \).
- \( R_n(x) \) is the remainder term, which gives the error of approximating the function by a polynomial of degree \( n \).
Remainder Term
The remainder term in the Taylor or Maclaurin series is crucial as it provides insight into how accurate the polynomial approximation is for a function within a specific interval. In essence, it captures the error left when the function is approximated by its first few terms. The remainder term \( R_n(x) \) is given by:\[ R_n(x) = \frac{f^{(n+1)}(c)(x-a)^{n+1}}{(n+1)!} \]Here, \( c \) is an unknown number that lies somewhere between \( a \) and \( x \).This term decreases as more terms are included in the series, leading to a more accurate function approximation.
- The size of \( R_n(x) \) hints at the interval where the polynomial provides a good approximation of the function.
- By evaluating the upper bound of this term, one can determine the precision of the Taylor expansion.
Derivatives
Derivatives represent the fundamental concept in calculus, capturing the rate at which a function changes. When constructing a Taylor or Maclaurin series, derivatives play a central role. They are the building blocks of these series, as each term in the polynomial is derived from them.For a function \( f(x) \), the derivatives used in a Taylor series are calculated as follows:
- First derivative, \( f'(x) \): Gives the instantaneous rate of change of \( f(x) \).
- Second derivative, \( f''(x) \): Represents the curvature or concavity of \( f(x) \).
- Higher derivatives, \( f^{(n)}(x) \): Extend these concepts to more complex changes.