Chapter 11: Problem 25
Determine whether the sequence converges or diverges, and if it converges, find the limit. $$ \left\\{\frac{4 n^{4}+1}{2 n^{2}-1}\right\\} $$
Short Answer
Expert verified
The sequence diverges.
Step by step solution
01
Analyze the Sequence
The given sequence is \( \left\{ \frac{4n^4 + 1}{2n^2 - 1} \right\} \). To determine if it converges, we need to consider its behavior as \( n \) approaches infinity.
02
Divide by the Dominant Term
For large \( n \), the dominant term in the numerator is \( 4n^4 \) and in the denominator is \( 2n^2 \). Divide both the numerator and the denominator by \( n^2 \), the highest power of \( n \) in the denominator: \[ \frac{4n^4+1}{2n^2-1} = \frac{4n^4/n^2 + 1/n^2}{2n^2/n^2 - 1/n^2} = \frac{4n^2 + \frac{1}{n^2}}{2 - \frac{1}{n^2}} \]
03
Simplify the Expression
As \( n \to \infty \), the terms \( \frac{1}{n^2} \) become negligible. Thus, the sequence simplifies to \[ \frac{4n^2}{2} = 2n^2 \]
04
Conclusion
Since the leading term \( 2n^2 \) goes to infinity as \( n \to \infty \), the sequence diverges. There is no finite limit to this sequence.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Dominant Term
When analyzing sequences, especially when determining convergence or divergence, identifying the **dominant term** can simplify the process significantly. The dominant term is the part of a mathematical expression or function that has the largest impact on its value as the variable within the expression grows. In the exercise given, the sequence is \( \frac{4n^4 + 1}{2n^2 - 1} \). As \( n \) becomes very large, the terms that influence the behavior the most are \( 4n^4 \) in the numerator and \( 2n^2 \) in the denominator.
- The dominant term in the numerator is \( 4n^4 \).
- The dominant term in the denominator is \( 2n^2 \).
Infinity Behavior
Understanding the **infinity behavior** of a sequence involves studying how it behaves as its variable, here represented as \( n \), grows without bound. In simpler terms, we want to know, "What happens to the sequence when \( n \) becomes very large?"By examining the simplified expression \( \frac{4n^2}{2 - \frac{1}{n^2}} \) derived from our original problem, we see that as \( n \to \infty \), the sequence more closely resembles \( \frac{4n^2}{2} = 2n^2 \). Here:
- The term \( \frac{1}{n^2} \) becomes negligible for very large \( n \), simplifying the denominator.
- The sequence's dominant term, as \( n \) heads towards infinity, shows an indefinite increase.
Limits of Sequences
A fundamental concept in understanding sequences is the idea of their **limits**. This involves determining whether a sequence approaches a particular number as the term number, \( n \), increases indefinitely.In our problem, after identifying and simplifying the dominant terms, what remains was the sequence \( 2n^2 \). This growth without restraint illustrates that the sequence does not converge to a limit. For a sequence to have a limit, its terms should approach a specific finite value as \( n \arrow \infty \).When we say a sequence converges:
- The values of the sequence get arbitrarily close to some number.
- As \( n \to \infty \), the difference between sequence values and the limit value approaches zero.