Chapter 1: Problem 13
Exer. 13-16: Solve the equation by using the quadratic formula. $$ x^{2}+4 x+2=0 $$
Short Answer
Expert verified
The roots are \( x = -2 + \sqrt{2} \) and \( x = -2 - \sqrt{2} \).
Step by step solution
01
Identify the Quadratic Equation Parameters
The given equation is in the form of \( ax^2 + bx + c = 0 \). Here, \( a = 1 \), \( b = 4 \), and \( c = 2 \). These are the coefficients we will use in the quadratic formula.
02
Recall the Quadratic Formula
The quadratic formula to find the roots of the equation \( ax^2 + bx + c = 0 \) is: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
03
Calculate the Discriminant
First, calculate the discriminant \( b^2 - 4ac \). Substitute the values: \( 4^2 - 4 \times 1 \times 2 = 16 - 8 = 8 \).
04
Check the Nature of Roots
The discriminant is \( 8 \), which is positive. This means the equation has two distinct real roots.
05
Apply the Quadratic Formula
Substitute \( a = 1 \), \( b = 4 \), and the discriminant into the quadratic formula: \[ x = \frac{-4 \pm \sqrt{8}}{2 \times 1} = \frac{-4 \pm 2\sqrt{2}}{2} \].
06
Simplify the Roots
Separate the expression: \[ x_1 = \frac{-4 + 2\sqrt{2}}{2} = -2 + \sqrt{2} \] and \[ x_2 = \frac{-4 - 2\sqrt{2}}{2} = -2 - \sqrt{2} \].
07
Verify the Solution
Substituting \( x_1 \, \text{and} \, x_2 \) back into the original equation confirms they satisfy the equation.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Equations
Quadratic equations are mathematical statements that take the form of \( ax^2 + bx + c = 0 \). They represent equations where the highest power of the unknown variable \( x \) is two. In this exercise, our given quadratic equation is \( x^2 + 4x + 2 = 0 \). Here, \( a \), \( b \), and \( c \) are coefficients which help define the parabola associated with the equation. For our particular example:
- \( a = 1 \)
- \( b = 4 \)
- \( c = 2 \)
Discriminant
The discriminant is an essential part of the quadratic formula, which helps us understand the nature of the roots of the equation. It is given by the expression \( b^2 - 4ac \) within the quadratic formula:\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]For our equation \( x^2 + 4x + 2 = 0 \), we calculate the discriminant using:
- \( b = 4 \)
- \( a = 1 \)
- \( c = 2 \)
Nature of Roots
Exploring the nature of roots tells us about the characteristics of the solutions of a quadratic equation. The nature of roots depends entirely on the value of the discriminant \( b^2 - 4ac \):
- If the discriminant is positive, the equation has two distinct real roots.
- If the discriminant is zero, the equation has exactly one real root, often called a repeated or double root.
- If the discriminant is negative, there are no real roots; instead, the roots are complex or imaginary.
Real Roots
Real roots of a quadratic equation are the solutions that are real numbers, not imaginary or complex numbers. For our equation \( x^2 + 4x + 2 = 0 \), the quadratic formula gives us the roots:\[ x = \frac{-4 \pm 2\sqrt{2}}{2} \]By simplifying, we find:
- First root: \( x_1 = -2 + \sqrt{2} \)
- Second root: \( x_2 = -2 - \sqrt{2} \)