/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 (a) Suppose that \(f\) is twice ... [FREE SOLUTION] | 91影视

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(a) Suppose that \(f\) is twice differentiable on \((0 . \infty)\) and that \(|f(x)| \leq M_{0}\) for all \(x>0,\) while \(\left|f^{\prime \prime}(x)\right| \leq M_{2}\) for all \(x>0 .\) Use an appropriate Taylor polynomial to prove that for any \(x>0\) we have $$\left|f^{\prime}(x)\right| \leq \frac{2}{h} M_{0}+\frac{h}{2} M_{2} \quad \text { for all } h>0.$$ (b) Show that for all \(x>0\) we have $$\left|f^{\prime}(x)\right| \leq 2 \sqrt{M_{0} M_{2}}$$ Hint: Consider the smallest value of the expression appearing in (a). (c) If \(f\) is twice differentiable on \((0 . \infty), f^{\prime \prime}\) is bounded, and \(f(x)\) approaches 0 as \(x \rightarrow \infty,\) then also \(f^{\prime}(x)\) approaches 0 as \(x \rightarrow \infty\) (d) If \(\lim _{x \rightarrow \infty} f(x)\) exists and \(\lim _{x \rightarrow \infty} f^{\prime \prime}(x)\) exists, then \(\lim _{x \rightarrow \infty} f^{\prime \prime}(x)=\lim _{x \rightarrow \infty} f^{\prime}(x)=0.\) (Compare Problem 11-34).

Short Answer

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Step by step solution

01

Use Taylor Polynomial

Consider the Taylor polynomial for the function
02

Taylor's Theorem

Using Taylor's theorem:
03

Derivative Bound

Using the conditions given,
04

Step 4. Optimal Value

Now, find
05

Demonstrate Limits

To show limit

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Taylor Polynomial
A Taylor polynomial is a powerful tool in calculus. It approximates a function near a specific point using the function鈥檚 derivatives.
Taylor polynomials can help solve complex problems by transforming them into simpler polynomial equations.
For instance, you can use the Taylor polynomial to approximate functions that are twice differentiable.
This means you can express the function in terms of its value and derivatives at a particular point.
For a twice differentiable function 饾憮 with derivatives bounded by \(M_0\) and \(M_2\), the Taylor polynomial helps us approximate \( f \) and its derivatives.
Twice Differentiable Function
A function is twice differentiable if both the function and its first and second derivatives exist and are continuous.
This property is crucial for ensuring the polynomial approximations we make (using tools like Taylor Polynomials) are accurate.
In problems with twice differentiable functions, you might be asked to use the second derivative, \( f''(x) \), to form additional constraints or approximations.
Bounded Derivatives
Bounded derivatives refer to derivatives that do not exceed certain values within a specified interval.
For instance, if a function \( f \) is such that \(|f(x)|\leq M_0\) and \(\left|f''(x)\right| \leq M_2\), these bounds help us constrain the values of the function and its derivatives.
For example, bounded derivatives are critical when deriving inequalities, such as proving bounds on \(\left|f'(x)\right|\).
In the given exercise, the function鈥檚 first derivative bound is derived using the constraint provided by bounded second derivatives.
Limits
Limits are fundamental in calculus, allowing us to understand the behavior of functions as they approach specific points.
In the exercise, you are asked to consider the limits as \( x \to \infty \).
This involves analyzing how the function \( f(x) \), its first derivative \( f'(x) \), and second derivative \( f''(x) \) behave as \( x \) grows very large.
Using the hints provided, you can show that if \( f(x) \to 0 \) as \( x \to \infty \), then indeed \( f'(x) \to 0 \) and \( f''(x) \to 0 \) under appropriate conditions.

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Most popular questions from this chapter

(a) Prove that the Taylor polynomial of \(f(x)=\sin \left(x^{2}\right)\) of degree \(4 n+2\) at 0 $$x^{2}-\frac{x^{6}}{3 !}+\frac{x^{10}}{5 !}-\cdots+(-1)^{n} \frac{x^{4 n+2}}{(2 n+1) !}.$$ Hint: If \(P\) is the Taylor polynomial of degree \(2 n+1\) for \(\sin\) at \(0 .\) then \(\sin x=P(x)+R(x),\) where \(\lim R(x) / x^{2 n+1}=0 .\) What does this imply about \(\lim _{x \rightarrow 0} R\left(x^{2}\right) / x^{4 n+2} ?\) (b) Find \(f^{(k)}(0)\) for all \(k\). (c) In general, if \(f(x)=g\left(x^{m}\right)\), find \(f^{(k)}(0)\) in terms of the derivatives of \(g\) at 0. The ideas in this problem can be extended significantly, in ways that are explored in the next three problems.

(a) Prove that if \(f^{\prime \prime}(a)\) exists, then $$f^{\prime \prime}(a)=\lim _{h \rightarrow 0} \frac{f(a+h)+f(a-h)-2 f(a)}{h^{2}}.$$ The limit on the right is called the Schwarz second derivative of \(f\) at a. Hint: Use the Taylor polynomial \(P_{2, a}(x)\) with \(x=a+h\) and with \(x=a-h\) (b) Let \(f(x)=x^{2}\) for \(x \geq 0,\) and \(-x^{2}\) for \(x \leq 0 .\) Show that $$\lim _{h \rightarrow 0} \frac{f(0+h)+f(0-h)-2 f(0)}{h^{2}}$$ exists, even though \(f^{\prime \prime}(0)\) does not. (c) Prove that if \(f\) has a local maximum at \(a,\) and the Schwarz second derivative of \(f\) at \(a\) exists, then it is \(\leq 0\). (d) Prove that if \(f^{\prime \prime \prime}(a)\) exists, then $$\frac{f^{\prime \prime \prime}(a)}{3}=\lim _{h \rightarrow 0} \frac{f(a+h)-f(a-h)-2 h f^{\prime}(a)}{h^{3}}.$$

(a) Let \(f(x)=x^{4} \sin 1 / x^{2}\) for \(x \neq 0,\) and \(f(0)=0 .\) Show that \(f=0\) up to order 2 at \(0,\) even though \(f^{\prime \prime}(0)\) does not exist. This example is slightly more complex, but also slightly more impressive, than the example in the text, because both \(f^{\prime}(a)\) and \(f^{\prime \prime}(a)\) exist for \(a \neq 0 .\) Thus, for each number \(a\) there is another number \(m(a)\) such that $$(*) \quad f(x)=f(a)+f^{\prime}(a)(x-a)+\frac{m(a)}{2}(x-a)^{2}+R_{a}(x),$$ $$\text { where } \lim _{x \rightarrow a} \frac{R_{a}(x)}{(x-a)^{2}}=0;$$ namely, \(m(a)=f^{\prime \prime}(a)\) for \(a \neq 0,\) and \(m(0)=0 .\) Notice that the function \(m\) defined in this way is not continuous. (b) Suppose that \(f\) is a differentiable function such that \((*)\) holds for all \(a\) with \(m(a)=0 .\) Use Problem 27 to show that \(f^{\prime \prime}(a)=m(a)=0\) for all \(a\). (c) Now suppose that \((*)\) holds for all \(a\), and that \(m\) is continuous. Prove that for all \(a\) the second derivative \(f^{\prime \prime}(a)\) exists and equals \(m(a)\).

Use the Taylor polynomial \(P_{1, a, f},\) together with the remainder, to prove a weak form of Theorem 2 of the Appendix to Chapter 11: If \(f^{\prime \prime}>0,\) then the graph of \(f\) always lies above the tangent line of \(f,\) except at the point of contact.

Let $$f(x)=\left\\{\begin{array}{ll} \frac{e^{x}-1}{x}, & x \neq 0 \\ 1, & x=0. \end{array}\right.$$ (a) Find the Taylor polynomial of degree \(n\) for \(f\) at \(0,\) compute \(f^{(k)}(0),\) and give an estimate for the remainder term \(R_{n, 0, f}\). (b) Compute \(\int_{0}^{1} f\) with an error of less than \(10^{-4}\).

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