Chapter 6: Problem 123
For the following exercises, determine whether the vector field is conservative and, if so, find a potential function. $$ \mathbf{F}(x, y, z)=(2 x y) \mathbf{i}+\left(x^{2}+2 y z\right) \mathbf{j}+y^{2} \mathbf{k} $$
Short Answer
Expert verified
The vector field is conservative. The potential function is \( \phi(x, y, z) = x^2y + y^2z + C \).
Step by step solution
01
Check if the Vector Field is Conservative
A vector field \( \mathbf{F} = P\mathbf{i} + Q\mathbf{j} + R\mathbf{k} \) is conservative if its curl is zero. Let's calculate the curl of \( \mathbf{F}(x, y, z) = (2xy) \mathbf{i} + (x^2 + 2yz) \mathbf{j} + y^2 \mathbf{k} \). The curl \( abla \times \mathbf{F} \) is given by the determinant:\[abla \times \mathbf{F} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\frac{\partial}{\partial x} & \frac{\partial}{\partial y} & \frac{\partial}{\partial z} \2xy & x^2 + 2yz & y^2 \end{vmatrix}\]Expanding the determinant, we calculate each component as follows.
02
Calculate the Determinant Components
The \( \mathbf{i} \)-component is:\[\mathbf{i} \left( \frac{\partial}{\partial y}(y^2) - \frac{\partial}{\partial z}(x^2 + 2yz) \right) = \mathbf{i}(2y - 2y) = \mathbf{i}(0)\]The \( \mathbf{j} \)-component is:\[\mathbf{j} \left( \frac{\partial}{\partial z}(2xy) - \frac{\partial}{\partial x}(y^2) \right) = \mathbf{j}(0 - 0) = \mathbf{j}(0)\]The \( \mathbf{k} \)-component is:\[\mathbf{k} \left( \frac{\partial}{\partial x}(x^2 + 2yz) - \frac{\partial}{\partial y}(2xy) \right) = \mathbf{k}(2x - 2x) = \mathbf{k}(0)\]All components are zero, so \( abla \times \mathbf{F} = 0 \). \( \mathbf{F} \) is conservative.
03
Find the Potential Function
Since the field is conservative, we find a potential function \( \phi \) such that \( abla \phi = \mathbf{F} \). We solve the following equations:1. \( \frac{\partial \phi}{\partial x} = 2xy \)2. \( \frac{\partial \phi}{\partial y} = x^2 + 2yz \)3. \( \frac{\partial \phi}{\partial z} = y^2 \)From equation (1): Integrate with respect to \( x \) to get \( \phi(x, y, z) = x^2y + g(y, z) \).From equation (2): Differentiate \( \phi \) with respect to \( y \), and match it:\[\frac{\partial}{\partial y}(x^2y + g(y, z)) = x^2 + \frac{\partial g}{\partial y} = x^2 + 2yz \] \( \frac{\partial g}{\partial y} = 2yz \), so integrate with respect to \( y \) to get \( g(y, z) = y^2z + h(z) \).Thus, \( \phi(x, y, z) = x^2y + y^2z + h(z) \).
04
Determine the Function \( h(z) \)
Using equation (3), differentiate \( \phi \) with respect to \( z \):\[\frac{\partial}{\partial z}(x^2y + y^2z + h(z)) = y^2 + \frac{dh}{dz} = y^2\]Thus, \( \frac{dh}{dz} = 0 \), leading to \( h(z) = C \), where \( C \) is a constant.Therefore, the potential function is:\[\phi(x, y, z) = x^2y + y^2z + C\]
05
Conclusion
The vector field \( \mathbf{F}(x, y, z)=(2 x y) \mathbf{i}+(x^{2}+2 y z) \mathbf{j}+y^{2} \mathbf{k} \) is conservative, and a potential function is \( \phi(x, y, z) = x^2y + y^2z + C \) where \( C \) is a constant.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Potential Function
A potential function is a scalar function whose gradient results in a given vector field. In simpler terms, it is the function such that when you take its gradient, you get back the vector field you're working with. If a vector field is conservative, then a potential function exists for it. To find it, you integrate components of the vector field in terms of each variable while keeping consistency with all components.
To determine a potential function:
To determine a potential function:
- Integrate the component given for each variable separately.
- Adjust for any potential functions by considering constant terms that depend on other variables.
Curl of a Vector Field
The curl of a vector field is a vector operator that describes the infinitesimal rotation of the field. It is particularly useful when determining if a vector field is conservative. A vector field with zero curl is deemed conservative, meaning it has no rotational component and can be expressed as a gradient of some scalar potential function.
To compute the curl \(abla \times \mathbf{F}\), one typically uses the determinant of a matrix where:
To compute the curl \(abla \times \mathbf{F}\), one typically uses the determinant of a matrix where:
- The first row is the unit vectors \(\mathbf{i}, \mathbf{j}, \mathbf{k}\).
- The second row consists of partial derivative operators \(\frac{\partial}{\partial x}, \frac{\partial}{\partial y}, \frac{\partial}{\partial z}\).
- The third row consists of the components of the vector field \(P, Q, R\).
Partial Derivatives
Partial derivatives are a fundamental concept used to differentiate a function with several variables. Instead of differentiating with respect to all variables, you choose one variable at a time and hold others constant. This is crucial when working with vector fields because it allows calculation of individual component changes as needed.
For vector fields, when finding a potential function or computing the curl, you'll constantly use partial derivatives. For instance:
For vector fields, when finding a potential function or computing the curl, you'll constantly use partial derivatives. For instance:
- The expression \(\frac{\partial \phi}{\partial x}\) refers to the rate of change of \(\phi\) with respect to \(x\) while keeping \(y\) and \(z\) constant.
- This approach allows for integration or differentiation in steps to simplify complex fields.