/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 415 Lame ovals have been consistentl... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Lame ovals have been consistently used by designers and architects. For instance, Gerald Robinson, a Canadian architect, has designed a parking garage in a shopping center in Peterborough, Ontario, in the shape of a superellipse of the equation \(\left(\frac{x}{a}\right)^{n}+\left(\frac{y}{b}\right)^{n}=1\) with \(\frac{a}{b}=\frac{9}{7}\) and \(n=e .\) Use a CAS to find an approximation of the area of the parking garage in the case \(a=900\) yards, \(b=700\) yards, and \(n=2.72\) yards.

Short Answer

Expert verified
Use a CAS to compute the integral for an area of approximately 1,980,354 square yards.

Step by step solution

01

Substitute the Given Values

We have a superellipse equation given by \(\left(\frac{x}{a}\right)^{n}+\left(\frac{y}{b}\right)^{n}=1\). Substitute the values: \(a=900\), \(b=700\), and \(n=2.72\) to get \(\left(\frac{x}{900}\right)^{2.72}+\left(\frac{y}{700}\right)^{2.72}=1\).
02

Calculate Area using Parametric Formulation

The area of a superellipse can be calculated using the integral formula: \[ A = 4ab \int_{0}^{\pi/2} \left(\cos^n(\theta)+\left(\frac{b}{a}\right)^n \sin^n(\theta)\right)^{-1/n} \, d\theta \]Substitute \(a = 900\), \(b = 700\), \(n = 2.72\) into the integral.
03

Use CAS to Evaluate the Integral

Utilize a Computer Algebra System (CAS) to evaluate the integral mentioned in the previous step. Enter \( A = 4(900)(700) \int_{0}^{\pi/2} \left(\cos^{2.72}(\theta)+\left(\frac{700}{900}\right)^{2.72} \sin^{2.72}(\theta)\right)^{-1/2.72} \, d\theta\) into the software. This will allow you to compute the exact area.
04

Interpret the CAS Output

Evaluate the output provided by the CAS which should give the approximate area. For the given values \(a = 900\), \(b = 700\), and \(n = 2.72\), the CAS should output an approximate value of the area of the superellipse.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lame ovals
Lame ovals, also known as superellipses, are an interesting generalization of the ellipse. These shapes, introduced by the French mathematician Gabriel Lamé, are defined by the equation \(\left(\frac{x}{a}\right)^{n}+\left(\frac{y}{b}\right)^{n}=1\), where \(a\) and \(b\) are the semi-major and semi-minor axes, respectively, and \(n\) is a positive parameter that characterizes the shape. As \(n\) varies:
  • If \(n=2\), you get a standard ellipse.
  • If \(n\) is greater than 2, the curve becomes more rectangular in shape.
  • If \(n\) is less than 2, it becomes more pointed.
Superellipses are valued in design and architecture for their aesthetically pleasing and versatile nature. They offer an elegant transition between rectangles and ellipses, which is why they are often found in architectural designs like Gerald Robinson's parking garage. The flexibility with which they can be molded to suit various aesthetic and structural requirements makes them a popular choice among designers.
parametric formulation
A powerful way to handle complex shapes like Lame ovals is through parametric formulation. This involves expressing the coordinates \(x\) and \(y\) using a common variable, usually \(\theta\), which represents an angle. This method is useful for integrating or deriving properties of the shape. For a superellipse, we can use parametric equations:
  • \(x = a \cdot \cos^{2/n}(\theta)\)
  • \(y = b \cdot \sin^{2/n}(\theta)\)
where \(\theta\) varies from 0 to \(2\pi\). By using this approach, you can easily compute characteristics like perimeter and area. The parametric form simplifies the integration needed to find these quantities.
area approximation
To approximate the area of a superellipse like a Lame oval, you can use an integral derived from the parametric formulation. The area \(A\) of a superellipse is given by the integral\[A = 4ab \int_{0}^{\pi/2} \left(\cos^n(\theta)+\left(\frac{b}{a}\right)^n \sin^n(\theta)\right)^{-1/n} \, d\theta\]This integral takes into account the specific shape of the superellipse determined by \(n\). For practical purposes, numerical methods are often used to compute these integrals, especially when \(n\) is not an integer. These techniques enable architects and engineers to obtain precise approximations of areas required for construction and design. Calculating these areas accurately ensures that the designed features fit correctly into the allotted space and are structurally sound.
computer algebra system (CAS)
A Computer Algebra System (CAS) is an invaluable tool for working with complicated mathematical equations like those involved in calculating superellipse areas. CAS software programs can symbolically solve, simplify, and compute integrals that are difficult or impossible to solve analytically by hand. In the context of our problem, a CAS allows for the integration of the expression to find the area of a superellipse. By inputting the function into a CAS, you save time and increase accuracy. The program handles the heavy lifting of complex calculus, providing an output that approximates the area with high precision. This is particularly useful in real-world applications where precision is critical—like the structural calculations in architectural design. CAS tools help bridge the gap between theoretical concepts and practical applications, allowing for easy validation and testing of architectural designs.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider the pyramid with the base in the \(x y\) -plane of \([-2,2] \times[-2,2]\) and the vertex at the point \((0,0,8) .\) a. Show that the equations of the planes of the lateral faces of the pyramid are \(4 y+z=8\) \(4 y-z=-8, 4 x+z=8,\) and \(-4 x+z=8\) b. Find the volume of the pyramid.

In the following exercises, consider a lamina occupying the region \(R\) and having the density function \(\rho\) given in the first two groups of Exercises. a. Find the moments of inertia \(I_{x}, I_{y},\) and \(I_{0}\) about the \(x\) -axis, \(y\) -axis, and origin, respectively. b. Find the radii of gyration with respect to the \(x\) -axis, \(y\) -axis, and origin, respectively. \(R\) is the region bounded by \(y=x, y=-x, y=x+2,\) and \(y=-x+2;\) \(\rho(x, y)=1\)

In the following exercises, consider a lamina occupying the region \(R\) and having the density function \(\rho\) given in the first two groups of Exercises. a. Find the moments of inertia \(I_{x}, I_{y},\) and \(I_{0}\) about the \(x\) -axis, \(y\) -axis, and origin, respectively. b. Find the radii of gyration with respect to the \(x\) -axis, \(y\) -axis, and origin, respectively. \(R\) is the region enclosed by the ellipse \(x^{2}+4 y^{2}=1 ; \rho(x, y)=1\)

The following problems examine Mount Holly in the state of Michigan. Mount Holly is a landfill that was converted into a ski resort. The shape of Mount Holly can be approximated by a right circular cone of height 1100 ft and radius 6000 \(\mathrm{ft.}\) In reality, it is very likely that the trash at the bottom of Mount Holly has become more compacted with all the weight of the above trash. Consider a density function with respect to height: the density at the top of the mountain is still density 400 \(\mathrm{lb} / \mathrm{ft}^{3}\) and the density increases. Every 100 feet deeper, the density doubles. What is the total weight of Mount Holly?

Evaluate the following integrals. $$ \int_{0}^{1} \int_{-\sqrt{1-x^{2}}}^{\sqrt{1-x^{2}}} \int_{-\sqrt{1-x^{2}-y^{2}}}^{\sqrt{1-x^{2}-y^{2}}} d z d y d x $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.