Chapter 5: Problem 371
In the following exercises, the transformations \(T : S \rightarrow R\) are one- to-one. Find their related inverse transformations \(T^{-1} : R \rightarrow S\) \(x=\ln u, y=\ln (u v)\) where \(S=\\{(u, v) | u>0, v>0\\}\) and \(R=\mathrm{R}^{2}\)
Short Answer
Expert verified
The inverse transformation is \(T^{-1}(x, y) = (e^x, e^{y-x})\).
Step by step solution
01
Express the original transformations
We have the transformations:\[x = \ln u, \quad y = \ln (uv)\] Given that these transformations are one-to-one, we know that each pair \((x, y)\) corresponds to a unique \((u, v)\).
02
Solve for u in terms of x
The first transformation is \(x = \ln u\). To express \(u\) in terms of \(x\), we exponentiate both sides to get:\[u = e^x\]
03
Solve for uv in terms of y
The second transformation is \(y = \ln(uv)\).Once again, to express \(uv\) in terms of \(y\), we exponentiate both sides:\[uv = e^y\]
04
Substitute u from Step 2 into Step 3
We found that \(u = e^x\). Substitute this into the equation from Step 3:\[e^x v = e^y\] Solving for \(v\), we divide both sides by \(e^x\): \[v = \frac{e^y}{e^x} = e^{y-x}\]
05
Write the inverse transformation
The original transformation \(T\) maps \((u, v)\) to \((x, y)\). We found expressions for \(u\) and \(v\) in terms of \(x\) and \(y\):\[u = e^x, \quad v = e^{y-x}\] Hence, the inverse transformation \(T^{-1} : R \rightarrow S\) is given by:\[T^{-1}(x, y) = (e^x, e^{y-x})\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Logarithmic Functions
Logarithmic functions are a fundamental tool in mathematics, especially when dealing with exponential growth or decline. A logarithm essentially operates as the inverse of an exponential function. This means that if you have an exponential equation like \( y = b^x \), the logarithmic form is \( x = \log_b y \), provided that \( b > 0 \) and \( b eq 1 \).
For any positive real number \( y \), the logarithm gives us the power to which a fixed number, the base \( b \), must be raised to produce \( y \).
In the case of natural logarithms, the base \( b \) is Euler's number \( e \), approximately equal to 2.71828. Thus, the natural logarithm \( \ln x \) is the exponent to which \( e \) must be raised to obtain \( x \). For example, if \( x = \ln u \), it follows that \( u = e^x \).
This simplification makes logarithms especially useful for solving equations where the variable is located as an exponent.
For any positive real number \( y \), the logarithm gives us the power to which a fixed number, the base \( b \), must be raised to produce \( y \).
In the case of natural logarithms, the base \( b \) is Euler's number \( e \), approximately equal to 2.71828. Thus, the natural logarithm \( \ln x \) is the exponent to which \( e \) must be raised to obtain \( x \). For example, if \( x = \ln u \), it follows that \( u = e^x \).
This simplification makes logarithms especially useful for solving equations where the variable is located as an exponent.
- Simplifies multiplication and division into addition and subtraction.
- Converts exponential equations into linear ones, making them easier to solve.
Exponential Functions
Exponential functions are characterized by a constant base raised to a variable exponent. The general form of an exponential function is \( f(x) = a \cdot b^x \), where \( a \) is a constant and \( b \) is the base that is greater than zero and not equal to one.
These functions have a wide range of applications, from modeling population growth to calculating compound interest or radioactive decay. A critical feature of exponential functions is their rapid rate of change, which increases or decreases multiplicatively rather than additively.
In mathematics, the natural exponential function \( e^x \) has a special status due to its natural growth pattern. This function’s growth rate is proportional to its value, making it fundamental in calculus and differential equations.
These functions have a wide range of applications, from modeling population growth to calculating compound interest or radioactive decay. A critical feature of exponential functions is their rapid rate of change, which increases or decreases multiplicatively rather than additively.
In mathematics, the natural exponential function \( e^x \) has a special status due to its natural growth pattern. This function’s growth rate is proportional to its value, making it fundamental in calculus and differential equations.
- Useful for modeling continuous growth or decay over time.
- The inverse relationship with logarithmic functions allows for problem-solving versatility.
One-to-One Transformations
A one-to-one transformation ensures that each input corresponds to a unique output without any repetition. This property is crucial when determining the inverse transformation, as it guarantees that tracing back from the range to the domain is consistent.
For a transformation to be one-to-one, it must pass the horizontal line test on its graph: any horizontal line should intersect the graph at most once. This characteristic is vital for the invertibility of functions.
In mathematical terms, if \( T: A \rightarrow B \) is one-to-one, for any \( a_1, a_2 \in A \), \( T(a_1) = T(a_2) \) implies \( a_1 = a_2 \).
For a transformation to be one-to-one, it must pass the horizontal line test on its graph: any horizontal line should intersect the graph at most once. This characteristic is vital for the invertibility of functions.
In mathematical terms, if \( T: A \rightarrow B \) is one-to-one, for any \( a_1, a_2 \in A \), \( T(a_1) = T(a_2) \) implies \( a_1 = a_2 \).
- Facilitates constructing the inverse transformation, as every element in the range is paired with a unique element in the domain.
- Ensures data or values are not lost or unidentifiable when reversing a transformation.