Chapter 3: Problem 111
Find the length of the curve \(\mathbf{r}(t)=\left\langle\sqrt{2} t, e^{t}, e^{-t}\right\rangle\) over the interval \( 0 \leq t \leq 1 .\) The graph is shown here:
Short Answer
Expert verified
The length of the curve is \( e - \frac{1}{e} \).
Step by step solution
01
Understand the Problem
We need to find the length of the given vector function \( \mathbf{r}(t) = \langle \sqrt{2}t, e^t, e^{-t} \rangle \) from \( t = 0 \) to \( t = 1 \). The length of a curve described by a vector function from \( a \) to \( b \) is given by the integral \( L = \int_{a}^{b} \| \mathbf{r}'(t) \| \, dt \).
02
Find the Derivative of the Vector Function
Compute the derivative of \( \mathbf{r}(t) = \langle \sqrt{2}t, e^t, e^{-t} \rangle \). The derivative is \( \mathbf{r}'(t) = \langle \sqrt{2}, e^t, -e^{-t} \rangle \).
03
Calculate the Magnitude of the Derivative
To find \( \| \mathbf{r}'(t) \| \), compute the magnitude: \( \| \mathbf{r}'(t) \| = \sqrt{(\sqrt{2})^2 + (e^t)^2 + (-e^{-t})^2} = \sqrt{2 + e^{2t} + e^{-2t}} \).
04
Set Up the Integral for Curve Length
The length of the curve \( L \) is the integral from 0 to 1 of the magnitude found in Step 3: \( L = \int_{0}^{1} \sqrt{2 + e^{2t} + e^{-2t}} \, dt \).
05
Simplify the Integrand
Recognize \( e^{2t} + e^{-2t} \) can be rewritten as \( \left(e^t + e^{-t}\right)^2 - 2 \). Therefore, the integrand becomes \( \sqrt{\left(e^t + e^{-t}\right)^2} \). This simplifies to \( e^t + e^{-t} \).
06
Evaluate the Integral
Evaluate \( \int_{0}^{1} (e^t + e^{-t}) \, dt \) by finding the antiderivative: \( \int e^t \, dt = e^t \) and \( \int e^{-t} \, dt = -e^{-t} \). Thus, the integral becomes \([e^t - e^{-t}]_{0}^{1} = \left(e^1 - e^{-1}\right) - \left(e^0 - e^0\right) = e - \frac{1}{e} \).
07
Calculate the Final Answer
Substitute the limits: \( (e - \frac{1}{e}) - (1 - 1) = e - \frac{1}{e} \). Thus, the length of the curve is \( e - \frac{1}{e} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Curve Length
The concept of curve length is a fascinating topic in vector calculus. It refers to the total distance traveled along a curve in a vector field. When we have a vector function that describes a curve, we can calculate its length using integral calculus.
To find the curve length, we integrate the magnitude of the derivative of the vector function over a specified interval. For a vector function \(\mathbf{r}(t) = \langle x(t), y(t), z(t) \rangle\), the length L of the curve from \( t = a \) to \( t = b \) is given by:
To find the curve length, we integrate the magnitude of the derivative of the vector function over a specified interval. For a vector function \(\mathbf{r}(t) = \langle x(t), y(t), z(t) \rangle\), the length L of the curve from \( t = a \) to \( t = b \) is given by:
- \( L = \int_{a}^{b} \| \mathbf{r}'(t) \| \, dt \)
Vector Functions
Vector functions describe objects moving through space, and they are essential for modeling curves and trajectories in three-dimensional space. They use a parameter, often denoted by \( t \), to provide positions, called vectors, that change over time.
For the example exercise, the vector function \( \mathbf{r}(t) = \langle \sqrt{2} t, e^{t}, e^{-t} \rangle \) gives the position of a point as it moves along a curve. Each component of the vector function corresponds to a coordinate: \( x(t) = \sqrt{2} t \), \( y(t) = e^t \), and \( z(t) = e^{-t} \).
For the example exercise, the vector function \( \mathbf{r}(t) = \langle \sqrt{2} t, e^{t}, e^{-t} \rangle \) gives the position of a point as it moves along a curve. Each component of the vector function corresponds to a coordinate: \( x(t) = \sqrt{2} t \), \( y(t) = e^t \), and \( z(t) = e^{-t} \).
- Derivative of a Vector Function: Calculating \( \mathbf{r}'(t) \) finds how each component changes with respect to \( t \). It's vital for finding tangent vectors and determining curve length.
- In the exercise, the derivative was \( \mathbf{r}'(t) = \langle \sqrt{2}, e^t, -e^{-t} \rangle \).
Integral Calculus
Integral calculus plays a crucial role in determining quantities like areas, volumes, and lengths. When finding the length of a curve, we use integration to accumulate small elements of arc length to a total distance.
The process involves integrating the magnitude of the velocity vector, \( \| \mathbf{r}'(t) \| \), which represents the speed of moving along the curve: \( L = \int_{a}^{b} \| \mathbf{r}'(t) \| \, dt \).
The process involves integrating the magnitude of the velocity vector, \( \| \mathbf{r}'(t) \| \), which represents the speed of moving along the curve: \( L = \int_{a}^{b} \| \mathbf{r}'(t) \| \, dt \).
Importance of Integral Calculus:
- Allows calculation of cumulative quantities like curve length by summing infinitesimal contributions.
- Transforms problems of motion and fields into manageable calculations.