Chapter 2: Problem 9
For the following exercises, consider points \(P(-1,3)\) \(Q(1,5),\) and \(R(-3,7) .\) Determine the requested vectors and express each of them a. in component form and b. by using the standard unit vectors. The unit vector in the direction of \(\overrightarrow{P Q}\)
Short Answer
Expert verified
The unit vector in the direction of \(\overrightarrow{PQ}\) is \(\frac{1}{\sqrt{2}}\mathbf{i} + \frac{1}{\sqrt{2}}\mathbf{j}\).
Step by step solution
01
Calculate the Component Form of \(\overrightarrow{PQ}\)
To find the component form of \(\overrightarrow{PQ}\), subtract the coordinates of point \(P\) from the coordinates of point \(Q\). This gives us the difference in each coordinate:\[\overrightarrow{PQ} = (x_2 - x_1, y_2 - y_1) = (1 - (-1), 5 - 3) = (2, 2)\]So the component form of \(\overrightarrow{PQ}\) is \((2, 2)\).
02
Express \(\overrightarrow{PQ}\) Using Standard Unit Vectors
Standard unit vectors are expressed in terms of \(\mathbf{i}\) and \(\mathbf{j}\), which represent the unit vectors in the direction of the x-axis and y-axis, respectively. From the component form \((2, 2)\), \(\overrightarrow{PQ}\) can be expressed as:\[\overrightarrow{PQ} = 2\mathbf{i} + 2\mathbf{j}\]
03
Calculate the Magnitude of \(\overrightarrow{PQ}\)
The magnitude of a vector \((a, b)\) is calculated using the formula:\[\|\overrightarrow{PQ}\| = \sqrt{a^2 + b^2} = \sqrt{2^2 + 2^2} = \sqrt{8} = 2\sqrt{2}\]
04
Find the Unit Vector in the Direction of \(\overrightarrow{PQ}\)
A unit vector in the direction of a given vector is obtained by dividing each component of the vector by its magnitude. Thus, the unit vector \(\overrightarrow{u}\) in the direction of \(\overrightarrow{PQ}\) is:\[\overrightarrow{u} = \frac{1}{\|\overrightarrow{PQ}\|}(2, 2) = \left(\frac{2}{2\sqrt{2}}, \frac{2}{2\sqrt{2}}\right) = \left(\frac{1}{\sqrt{2}}, \frac{1}{\sqrt{2}}\right)\]Expressing this using standard unit vectors:\[\overrightarrow{u} = \frac{1}{\sqrt{2}}\mathbf{i} + \frac{1}{\sqrt{2}}\mathbf{j}\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Component Form
When working with vectors, the component form is a simplified way to describe a vector in terms of its horizontal and vertical components. Given two points, say \(P(x_1, y_1)\) and \(Q(x_2, y_2)\), you can find the vector \(\overrightarrow{PQ}\) by subtracting the coordinates of \(P\) from \(Q\):
This representation is essential because it illuminates the vector's path in a coordinate system.
- Horizontal component: \(x_2 - x_1\)
- Vertical component: \(y_2 - y_1\)
This representation is essential because it illuminates the vector's path in a coordinate system.
Unit Vector
A unit vector is a vector that has a magnitude of 1, pointing in a specific direction. It is often used to express the direction of a vector without considering its magnitude. To find a unit vector in the direction of a given vector \(\overrightarrow{v}\), you divide the vector by its magnitude.
- Unit vector formula: \(\overrightarrow{u} = \frac{\overrightarrow{v}}{\|\overrightarrow{v}\|}\)
- \(\overrightarrow{u} = \left(\frac{2}{2\sqrt{2}}, \frac{2}{2\sqrt{2}}\right) = \left(\frac{1}{\sqrt{2}}, \frac{1}{\sqrt{2}}\right)\)
Standard Unit Vectors
Standard unit vectors are predefined vectors that are used as a basis to express any vector in a two-dimensional plane. They are typically denoted as \(\mathbf{i}\) and \(\mathbf{j}\), where:
- \(\mathbf{i}\) is the unit vector along the x-axis: \((1, 0)\)
- \(\mathbf{j}\) is the unit vector along the y-axis: \((0, 1)\)
Magnitude of a Vector
The magnitude of a vector represents its length and is a measure of how far it extends from its initial point. Calculating the magnitude of a vector \((a, b)\) involves using the Pythagorean theorem, as the vector forms a right triangle with the axes.
- Magnitude formula: \(\|\overrightarrow{v}\| = \sqrt{a^2 + b^2}\)
- \(\|\overrightarrow{PQ}\| = \sqrt{2^2 + 2^2} = \sqrt{8} = 2\sqrt{2}\)