/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 67 Write the equation of the plane ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Write the equation of the plane passing through point \((1,1,1)\) that is parallel to the \(x y\) -plane.

Short Answer

Expert verified
The equation of the plane is \(z = 1\).

Step by step solution

01

Understand the Concept of Parallelism

A plane parallel to the \(xy\)-plane has a normal vector with a zero \(z\)-component. Thus, its equation can be expressed as \(z = c\), where \(c\) is a constant.
02

Identify the Value of the Constant

Since the plane must pass through the given point \((1,1,1)\), substitute \((x, y, z) = (1, 1, 1)\) into the general form of the plane equation \(z = c\).
03

Solve for the Constant \(c\)

Substitute \(z = 1\) for the point \((1, 1, 1)\) into the plane equation. This gives \(1 = c\), so \(c = 1\).
04

Write the Equation of the Plane

Using the solved constant \(c = 1\), the equation of the plane is \(z = 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

xy-plane
The xy-plane in three-dimensional space is a flat, two-dimensional surface where the z-coordinate is the same everywhere, usually taken to be zero. Imagine a sheet of paper meant to extend infinitely in the x and y directions, but having no thickness in the z direction. This plane is fundamental in 3D geometry.

In the context of planes and equations, the xy-plane provides a reference point. If a plane is parallel to the xy-plane, it implies that its orientation does not ever intersect the xy-plane. Only the z-dimension differs in its description and representation.

For any plane parallel to the xy-plane, the equation can be simplified to the form \(z = c\). Here, \(c\) is a constant defining the distance between the plane and the xy-plane along the z-axis. This means all points on the plane have the same z-value, corresponding directly to \(c\). Understanding this simple concept of the xy-plane is crucial to spatial reasoning in three dimensions.
normal vector
A normal vector is essential in determining the orientation of a plane in three dimensions. It is a vector that is perpendicular, or orthogonal, to the plane. Think of it as an arrow sticking straight out from the center of the plane—this helps define the plane’s tilt or angle in the 3D space.

To denote a plane, a normal vector is often represented as \(\vec{n} = (A, B, C)\). The coefficients \(A\), \(B\), and \(C\) relate directly to the implicit plane equation \(Ax + By + Cz = D\).

In the case of a plane parallel to the xy-plane, the normal vector’s z-component is zero, meaning \(C = 0\). This is because the plane is level with respect to the xy-plane, pointing directly up or down. The normal vector is then \(\vec{n} = (0, 0, C)\), and simplifies to just affecting the x and y directions, but making the z part constant in the plane, confirming the equation \(z = c\).
plane parallelism
Plane parallelism in three-dimensional geometry refers to two planes that never intersect, no matter how far they extend. If planes are parallel, they maintain a constant distance apart because they have the same orientation.

To determine if two planes are parallel, their normal vectors are critical. If the normal vectors of two planes are scalar multiples of each other, it confirms the planes are parallel. This is because the angles at which they stand in space are identical.

In our scenario about a plane being parallel to the xy-plane, this relationship shows through the vector orientation and equation simplification. By having a normal vector \(\vec{n} = (0, 0, 1)\) for the xy-plane, any plane with a normal vector \(\vec{n} = (0, 0, c)\) will be parallel to it, confirming there will be no intersection at any point along their infinite spans.

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Most popular questions from this chapter

For the following exercises, line L is given. a. Find point \(P\) that belongs to the line and direction vector \(\mathbf{v}\) of the line. Express \(\mathbf{v}\) in component form. b. Find the distance from the origin to line \(L\) \(x=1+t, y=3+t, z=5+4 t, t \in \mathbb{R}\)

Consider \(\mathbf{r}(t)=\langle\cos t, \sin t, 2 t\rangle\) the position vector of a particle at time \(t \in[0,30],\) where the components of \(\mathbf{r}\) are expressed in centimeters and time in seconds. Let \(\overrightarrow{O P}\) be the position vector of the particle after 1 sec. a. Determine unit vector \(\mathbf{B}(t)\) (called the bi normal unit vector) that has the direction of cross product vector \(\mathbf{v}(t) \times \mathbf{a}(t),\) where \(\mathbf{v}(t)\) and \(\mathbf{a}(t)\) are the instantaneous velocity vector and, respectively, the acceleration vector of the particle after \(t\) seconds. b. Use a CAS to visualize vectors \(\mathbf{v}(1), \mathbf{a}(1),\) and \(\mathbf{B}(1)\) as vectors statting at point \(P\) along with the path of the particle.

For the following exercises, the equation of a plane is given. a. Find normal vector \(\mathbf{n}\) to the plane. Express \(\mathbf{n}\) using standard unit vectors. b. Find the intersections of the plane with the axes of coordinates. c. Sketch the plane. \(3 x-2 y+4 z=0\)

For the following exercises, the equations of two planes are given. a. Determine whether the planes are parallel, orthogonal, or neither. b. If the planes are neither parallel nor orthogonal, then find the measure of the angle between the planes. Express the answer in degrees rounded to the nearest integer. [T] \(x-3 y+6 z=4, \quad 5 x+y-z=4\)

For the following exercises, lines \(L_{1}\) and \(L_{2}\) are given. Determine whether the lines are equal, parallel but not equal, skew, or intersecting. \(L_{1} : x=-1+2 t, y=1+3 t, z=7 t, \quad t \in \mathbb{R}\) and \(L_{2} : x-1=\frac{2}{3}(y-4)=\frac{2}{7} z-2\)

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