/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 59 A guy-wire supports a pole that ... [FREE SOLUTION] | 91Ó°ÊÓ

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A guy-wire supports a pole that is 75 ft high. One end of the wire is attached to the top of the pole and the other end is anchored to the ground 50 ft from the base of the pole. Determine the horizontal and vertical components of the force of tension in the wire if its magnitude is 50 lb. (Round to the nearest integer.)

Short Answer

Expert verified
The horizontal component is 33 lb, and the vertical component is 42 lb.

Step by step solution

01

Understand the Problem

You have a right triangle formed by the pole, the ground, and the guy-wire. The wire acts as the hypotenuse of the triangle, with the pole as the vertical side and the distance from the pole to the anchor point as the horizontal side.
02

Set Up Triangle Relations

Using the setup, the height of the pole can be labeled as 75 ft, while the horizontal distance from the base to where the wire is anchored is 50 ft. Express the horizontal and vertical components of the tension force using trigonometric identities.
03

Calculate the Wire's Angle with Ground

Use the tangent ratio in the triangle to find the angle \( \theta \) between the wire and the horizontal. The tangent of the angle is given by \( \tan(\theta) = \frac{75}{50} \). Compute \( \theta = \tan^{-1}(\frac{75}{50}) \).
04

Calculate Horizontal Tension Component

The horizontal component of the tension force \( T_x \) is given by \( T_x = T \cdot \cos(\theta) \). First, calculate \( \cos(\theta) \), then compute \( T_x = 50 \cdot \cos(\theta) \).
05

Calculate Vertical Tension Component

The vertical component of the tension force \( T_y \) is given by \( T_y = T \cdot \sin(\theta) \). First, calculate \( \sin(\theta) \), then compute \( T_y = 50 \cdot \sin(\theta) \).
06

Round the Components

Compute the final answers by rounding \( T_x \) and \( T_y \) to the nearest integer.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Right Triangle
In trigonometry, understanding right triangles is crucial. A right triangle is a type of triangle where one of the angles is exactly 90 degrees. The triangle formed in the problem involves a pole, the guy-wire, and the ground. Here, the pole is the vertical side, the distance from the pole's base to the wire's anchoring point is the horizontal side, and the wire itself is the hypotenuse.

This setup is important because it allows us to apply trigonometric ratios to solve for various components of the forces acting on the wire. The relationships between the sides are essential to finding out more about the tension forces involved. Knowing the lengths of the vertical and horizontal sides helps us calculate other aspects, such as the angle of the wire with the ground, and subsequently, the components of tension.

Understanding the layout of a right triangle helps us apply trigonometric identities effectively later. As the wire is the hypotenuse, it is the longest side, which stretches diagonally across the triangle's right angle. This forms the basis of how tension and trigonometry come into play in the problem.
Tension Force
Tension force is the pulling force experienced by a string, cable, or wire when it is pulled tight by forces acting from opposite ends. In our scenario, the tension force is created by the guy-wire keeping the pole upright. This force has two components: a horizontal component and a vertical component, based on its inclination to the ground.

When assessing tension in a wire like this, it’s essential to break it down into these components because they act in perpendicular directions:
  • Horizontal Component: This is the part of the tension parallel to the ground.
  • Vertical Component: This is the part of the tension perpendicular to the ground.
Both components tell us how the tension is distributed and how it helps maintain the stability of the pole.

By using trigonometric identities, we can derive these components from the total tension force, which is given as 50 lb in this problem. Understanding how tension operates on multiple levels is key to solving problems involving support mechanisms like guy-wires.
Trigonometric Identities
Trigonometric identities are mathematical equations derived from the properties of a right triangle. They are essential tools for finding relationships between the angles and sides of a triangle. The most commonly used identities are sine (\(\sin\)), cosine (\(\cos\)), and tangent (\(\tan\)), each of which helps in calculating different angle measures and proportions.

For the problem at hand, these identities allow us to break down the total tension force into its horizontal and vertical components. Steps involve:
  • Calculating the angle of the wire with the ground using the tangent function: \(\tan(\theta) = \frac{75}{50}\).
  • Using the angle to determine the horizontal and vertical components with cosine and sine, respectively: \(\cos(\theta)\) for horizontal and \(\sin(\theta)\) for vertical.
These calculations provide a clear understanding of the tension distribution along the wire.

In essence, without trigonometric identities, it becomes exceedingly challenging to ascertain how forces are resolved in right triangles, making them indispensable in the study of geometry and physics problems like the one presented.

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Most popular questions from this chapter

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