Chapter 2: Problem 427
For the following exercises, use the given vectors to find the quantities. \(\mathbf{a}=9 \mathbf{i}-2 \mathbf{j}, \mathbf{b}=-3 \mathbf{i}+\mathbf{j}\) a. \(3 \mathbf{a}+\mathbf{b}\) b. \(|\mathbf{a}|\) c. \(\mathbf{a} \times|\mathbf{b} \times| \mathbf{a}\) d. \( \mathbf{b} \times | \mathbf{a}\)
Short Answer
Step by step solution
Find 3a
Compute 3a + b
Calculate the magnitude of a
Prepare to find a cross |b| and |a|
Possible Interpretation for c: Cross-product a x (magnitude b)
Compute b cross magnitude(a) if resolved similarly, using b and a result
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Addition
When adding vectors, you simply add their corresponding components together. For the given vectors,
- The vector \( \mathbf{a} = 9 \mathbf{i} - 2 \mathbf{j} \)
- The vector \( \mathbf{b} = -3 \mathbf{i} + \mathbf{j} \)
To perform vector addition such as \( 3\mathbf{a} + \mathbf{b} \), you first need to scale \( \mathbf{a} \) by 3, which gives \( 3\mathbf{a} = 27\mathbf{i} - 6\mathbf{j} \). Then, add the scaled vector to \( \mathbf{b} \):
- Combine i-components: \(27 - 3 = 24 \)
- Combine j-components: \(-6 + 1 = -5 \)
Magnitude of a Vector
For a vector \( \mathbf{a} = 9 \mathbf{i} - 2 \mathbf{j} \), the magnitude \(|\mathbf{a}|\) is the square root of the sum of the squares of its components. The formula to find the magnitude \(|\mathbf{v}|\) for a vector \( \mathbf{v} = a\mathbf{i} + b\mathbf{j} \) is given by: \[|\mathbf{v}| = \sqrt{a^2 + b^2}\] Applying this to vector \( \mathbf{a} \):
- Compute squares: \(9^2 = 81\) and \((-2)^2 = 4\)
- Sum the squares: \(81 + 4 = 85\)
- Take the square root: \(\sqrt{85}\)
Cross Product
It is applicable for three-dimensional vectors. In our exercise, mismatched terms bring curiosity. Cross products usually look like \( \mathbf{a} \times \mathbf{b} \), and the calculated vector points orthogonally to both vectors. The magnitude of such a resulting vector in 3D is: \[|\mathbf{a} \times \mathbf{b}| = |\mathbf{a}||\mathbf{b}|\sin(\theta)\] Where \( \theta \) is the angle between the vectors. Since part c may be misinterpreted, rational methods suggest unit vector alignment:
- Magnitude approximations reflect vector scaling.
- Cross products evoke physical concepts, like torque.
Vector Multiplication
Understanding these types is important for approaching problems effectively. A common form of vector multiplication is scalar multiplication, where each vector component is multiplied by a constant.
This was seen when calculating \( 3\mathbf{a} \), which involved multiplying 9 by 3 and -2 by 3 to scale all components. Another is the dot product, providing a scalar outcome used to measure similarity in direction.Rare mislabels like 'b cross magnitude(a)' imply logical conflict.
Instead when setups specify, look to magnitude-oriented corrections, use
- Dot products for cosine angle applications.
- Scalar approximations when conveying runtime value.