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Consider \(\mathbf{u}\) and \(\mathbf{v}\) two three-dimensional vectors. If the magnitude of the cross product vector \(\mathbf{u} \times \mathbf{v}\) is \(k\) times larger than the magnitude of vector \(\mathbf{u},\) show that the magnitude of \(\mathbf{v}\) is greater than or equal to \(k,\) where \(k\) is a natural number.

Short Answer

Expert verified
The magnitude of vector \(\mathbf{v}\) is at least \(k\).

Step by step solution

01

Understanding Vector Magnitude and Cross Product

The magnitude of a cross product vector \( \|\mathbf{u} \times \mathbf{v}\| \) is equal to the product of the magnitudes of the vectors \( \mathbf{u} \) and \( \mathbf{v} \) and the sine of the angle \( \theta \) between them. This can be expressed mathematically as:\[\|\mathbf{u} \times \mathbf{v}\| = \|\mathbf{u}\| \cdot \|\mathbf{v}\| \cdot \sin(\theta)\]Given, \( \|\mathbf{u} \times \mathbf{v}\| = k \cdot \|\mathbf{u}\| \).
02

Substituting Given Information

From the formula for the cross product magnitude:\[\|\mathbf{u}\| \cdot \|\mathbf{v}\| \cdot \sin(\theta) = k \cdot \|\mathbf{u}\|\]Dividing both sides by \( \|\mathbf{u}\| \), we get:\[\|\mathbf{v}\| \cdot \sin(\theta) = k\]
03

Analyzing the Sine Component

Since \( \sin(\theta) \) can be a maximum of 1, it follows that: \[\|\mathbf{v}\| \cdot \sin(\theta) \leq \|\mathbf{v}\|\] Therefore, if \( \|\mathbf{v}\| \cdot \sin(\theta) = k \),then \( k \leq \|\mathbf{v}\| \). This shows that the magnitude of \( \mathbf{v} \) must be at least \( k \) for the initial condition to hold.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnitude of Vectors
The magnitude of a vector is a crucial concept in understanding vector operations, including the cross product. Think of vector magnitude as the "length" or "size" of a vector. It's usually represented by two vertical bars around the vector, like this: \( \|\mathbf{v}\| \). This notation signifies the length of a vector \( \mathbf{v} \) in space, much like the length of a line if you were to stretch it out on paper.
To calculate the magnitude of a vector, especially for a three-dimensional vector like \( \mathbf{v} = (v_1, v_2, v_3) \), use the formula:
  • \( \|\mathbf{v}\| = \sqrt{v_1^2 + v_2^2 + v_3^2} \)
In our exercise, knowing the magnitude is key to understanding the overall size and direction of the vector elements involved, particularly when exploring the cross product's effect on them.
Intuitively, when discussing magnitudes in vector cross products, remember they reflect how "strong" a vector is in contributing to the overall product.
Sine of Angle Between Vectors
The sine of the angle between vectors plays a pivotal role in the cross product. When you take the cross product of two vectors \( \mathbf{u} \) and \( \mathbf{v} \), the angle \( \theta \) between them affects the resulting magnitude. Mathematically, the cross product's magnitude can be calculated using:
  • \( \|\mathbf{u} \times \mathbf{v}\| = \|\mathbf{u}\| \times \|\mathbf{v}\| \times \sin(\theta) \)
The term \( \sin(\theta) \) (where \( \theta \) is the angle between vectors \( \mathbf{u} \) and \( \mathbf{v} \)) measures the perpendicular "effect" the vectors have on each other.
This effect reaches its maximum when the vectors are perpendicular—that is, \( \sin(\theta) = 1 \). This is why, in our example, we consider the case where \( \sin(\theta) \) could be at its maxima for analyzing magnitudes. It ensures that for any non-zero angle, the sine value is at most 1, not exceeding the magnitude of \( \|\mathbf{v}\| \).
Three-Dimensional Vectors
Three-dimensional vectors are fundamental units in mathematics and physics, especially when performing vector operations such as the cross product. These vectors have three components: \( x \), \( y \), and \( z \), each representing a direction in three-dimensional space.
Visually, you can imagine three-dimensional vectors as arrows originating from the origin in a 3D coordinate system. Each component \( v_1, v_2, v_3 \) denotes the vector's influence or "movement" along the coordinate axes.
  • In the vector notation, a vector \( \mathbf{v} = (v_1, v_2, v_3) \) points to a position relative to the origin defined by these components.
Understanding these vectors includes grasping how they interact under different operations, specifically their role in forming a new vector by the cross product. The dimensionality allows for finding perpendicular vectors easily, which is significant when exploring vector geometry or physics problems. The uniqueness of the cross product lies in this 3D aspect, providing insights into directions and magnitudes relevant for diverse applications.

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Most popular questions from this chapter

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