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For the following exercises, consider points \(P(-1,3)\) \(Q(1,5),\) and \(R(-3,7) .\) Determine the requested vectors and express each of them a. in component form and b. by using the standard unit vectors. $$ \overrightarrow{P R} $$

Short Answer

Expert verified
Vector \(\overrightarrow{PR}\) is \((-2, 4)\) or \(-2\mathbf{i} + 4\mathbf{j}\).

Step by step solution

01

Understand Component Form of a Vector

The component form of a vector from point \(A(x_1, y_1)\) to point \(B(x_2, y_2)\) is found using the differences in each coordinate: \(\overrightarrow{AB} = (x_2 - x_1, y_2 - y_1)\). This formula will help us find the vector \(\overrightarrow{PR}\).
02

Calculate the Component Form of \(\overrightarrow{PR}\)

Given points \(P(-1, 3)\) and \(R(-3, 7)\), calculate the components of \(\overrightarrow{PR}\) using the formula from Step 1: - For the x-component: \((-3) - (-1) = -3 + 1 = -2\).- For the y-component: \(7 - 3 = 4\).Thus, the component form of \(\overrightarrow{PR}\) is \((-2, 4)\).
03

Express the Vector using Standard Unit Vectors

Vector components can also be expressed using the standard unit vectors \(\mathbf{i}\) and \(\mathbf{j}\), where \(\mathbf{i}\) represents the x-axis and \(\mathbf{j}\) represents the y-axis. The vector \((-2, 4)\) can be written as \(-2\mathbf{i} + 4\mathbf{j}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Component Form of Vectors
The component form of a vector is a way to describe the vector using horizontal and vertical directions. It shows how far you move along each axis to go from one point to another. To find the component form of a vector from point \( A(x_1, y_1) \) to point \( B(x_2, y_2) \), you use the formula: \[ \overrightarrow{AB} = (x_2 - x_1, y_2 - y_1) \] This formula computes the change in x (x-component) and the change in y (y-component).
For example, to find the vector \( \overrightarrow{PR} \) from point \( P(-1, 3) \) to point \( R(-3, 7) \), calculate:
  • Change in x: \( -3 - (-1) = -2 \)
  • Change in y: \( 7 - 3 = 4 \)
So, the component form of \( \overrightarrow{PR} \) is \( (-2, 4) \). This tells us to move 2 units left and 4 units up.
Standard Unit Vectors
Standard unit vectors help us express vectors in a clear and structured way. These unit vectors are the building blocks:
  • \( \mathbf{i} \) represents one unit along the x-axis.
  • \( \mathbf{j} \) represents one unit along the y-axis.
Any vector can be broken down into a sum of these unit vectors. For example, the vector in component form \( (-2, 4) \) can be expressed using unit vectors as: \[-2\mathbf{i} + 4\mathbf{j} \] This tells us the vector moves 2 units in the negative x-direction and 4 units in the positive y-direction. These expressions make it easy to understand and visualize vectors geometrically.
Vector Subtraction
Vector subtraction involves finding the difference between two vectors. It's similar to how you subtract numbers. If you have vectors \( \overrightarrow{u} = (u_1, u_2) \) and \( \overrightarrow{v} = (v_1, v_2) \), their subtraction is: \[ \overrightarrow{u} - \overrightarrow{v} = (u_1 - v_1, u_2 - v_2) \] This method of subtraction is used to derive vectors, such as finding a vector between two points.

For example, to find the vector from \( P \) to \( R \), calculate the difference in their coordinates:
  • x-component: \( -3 - (-1) = -2 \)
  • y-component: \( 7 - 3 = 4 \)
Thus, the subtraction operation helps to reveal the direction and distance from one point to another.
Coordinate Geometry
Coordinate geometry allows us to use algebra and geometry together to solve problems. In this field, vectors play a key role by providing a way to describe figures in the plane, like lines and triangles, precisely.

By using vectors, we can analytically study the properties of geometric shapes through their coordinates. For instance, the vector \( \overrightarrow{PR} = (-2, 4) \) tells us that from point \( P(-1, 3) \) to \( R(-3, 7) \), we move negatively along the x-axis and positively along the y-axis.

Thus, vectors help in calculating distances, directions, and can even describing transformations such as rotations and translations, making them indispensable in coordinate geometry.

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Most popular questions from this chapter

For the following exercises, lines \(L_{1}\) and \(L_{2}\) are given. Determine whether the lines are equal, parallel but not equal, skew, or intersecting. \(L_{1} : x=-1+2 t, y=1+3 t, z=7 t, \quad t \in \mathbb{R}\) and \(L_{2} : x-1=\frac{2}{3}(y-4)=\frac{2}{7} z-2\)

[T] A solar panel is mounted on the roof of a house. The panel may be regarded as positioned at the points of coordinates (in meters) \(A(8,0,0)\), \(B(8,18,0)\), \(C(0,18,8)\) and \(D(0,0,8)\) (see the following figure). a. Find the general form of the equation of the plane that contains the solar panel by using points A, B, and C, and show that its normal vector is equivalent to \(\overrightarrow{A B} \times \overrightarrow{A D}\) b. Find parametric equations of line \(L_{1}\) that passes through the center of the solar panel and has direction vector \(\mathbf{s}=\frac{1}{\sqrt{3}} \mathbf{i}+\frac{1}{\sqrt{3}} \mathbf{j}+\frac{1}{\sqrt{3}} \mathbf{k}, \quad\) which points toward the position of the Sun at a particular time of day. c. Find symmetric equations of line \(L_{2}\) that passes through the center of the solar panel and is perpendicular to it. d. Determine the angle of elevation of the Sun above the solar panel by using the angle between lines \(L_{1}\) and \(L_{2}\)

[T] John allocates \(d\) dollars to consume monthly three goods of prices a, b, and c. In this context, the budget equation is defined as \(a x+b y+c z=d\) where \(x \geq 0, y \geq 0\) and \(z \geq 0\) represent the number of items bought from each of the goods. The budget set is given by \(\\{(x, y, z) | a x+b y+c z \leq d, x \geq 0, y \geq 0, z \geq 0\) and the budget plane is the part of the plane of equation \(a x+b y+c z=d\) for which \(x \geq 0, y \geq 0\), \(x \geq 0, y \geq 0\), and \(z \geq 0\) Consider \(a=\$ 8\), \(b=\$ 5\), \(c=\$ 10\) and \(d=\$ 500\). a. Use a CAS to graph the budget set and budget plane. b. For \(z=25,\) find the new budget equation and graph the budget set in the same system of coordinates.

For the following exercises, the equation of a plane is given. a. Find normal vector \(\mathbf{n}\) to the plane. Express \(\mathbf{n}\) using standard unit vectors. b. Find the intersections of the plane with the axes of coordinates. c. Sketch the plane. \(3 x+4 y-12=0\)

The force vector \(\mathbf{F}\) acting on a proton with an electric charge of \(1.6 \times 10^{-19} \mathrm{C}\) (in coulombs) moving in a magnetic field \(\mathbf{B}\) where the velocity vector \(\mathbf{v}\) is given by \(\mathbf{F}=1.6 \times 10^{-19}(\mathbf{v} \times \mathbf{B})\) (here, \(\mathbf{v}\) is expressed in meters per second, \(\mathbf{B}\) is in tesla \([\mathrm{T}],\) and \(\mathbf{F}\) is in newtons \([\mathrm{N}] )\) . Find the force that acts on a proton that moves in the \(x y\) -plane at velocity \(\mathbf{v}=10^{5} \mathbf{i}+10^{5} \mathbf{j}\) (in meters per second) in a magnetic field given by \(\mathbf{B}=0.3 \mathbf{j} .\)

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