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Show that \(\mathbf{v} \times \mathbf{u}\) is orthogonal to \((\mathbf{u} \cdot \mathbf{v})(\mathbf{u}+\mathbf{v})+\mathbf{u},\) where \(\mathbf{u}\) and \(\mathbf{v}\) are nonzero vectors.

Short Answer

Expert verified
The vector is orthogonal because the dot product with \(\mathbf{v} \times \mathbf{u}\) is zero.

Step by step solution

01

Understand the Cross Product Properties

For vectors \(\mathbf{u}\) and \(\mathbf{v}\), the cross product, \(\mathbf{v} \times \mathbf{u}\), yields a vector that is orthogonal to both \(\mathbf{u}\) and \(\mathbf{v}\). This means any vector resulting from \(\mathbf{v} \times \mathbf{u}\) is perpendicular to both \(\mathbf{u}\) and \(\mathbf{v}\).
02

Simplify the Given Vector Expression

The expression given is \((\mathbf{u} \cdot \mathbf{v})(\mathbf{u}+\mathbf{v}) + \mathbf{u}\). Expand it to understand its components:\[(\mathbf{u} \cdot \mathbf{v})\mathbf{u} + (\mathbf{u} \cdot \mathbf{v})\mathbf{v} + \mathbf{u}.\]
03

Find the Dot Product with \(\mathbf{v} \times \mathbf{u}\)

We need to show that \((\mathbf{u} \cdot \mathbf{v})(\mathbf{u}+\mathbf{v}) + \mathbf{u}\) is orthogonal to \(\mathbf{v} \times \mathbf{u}\). This requires showing the dot product equals zero:\[((\mathbf{u} \cdot \mathbf{v})\mathbf{u} + (\mathbf{u} \cdot \mathbf{v})\mathbf{v} + \mathbf{u}) \cdot (\mathbf{v} \times \mathbf{u}) = 0.\]
04

Simplify Each Term in the Dot Product

Calculate separately:1. \(((\mathbf{u} \cdot \mathbf{v})\mathbf{u}) \cdot (\mathbf{v} \times \mathbf{u}) = (\mathbf{u} \cdot \mathbf{v}) \cdot 0 = 0.\)2. \((\mathbf{u} \cdot \mathbf{v})\mathbf{v} \cdot (\mathbf{v} \times \mathbf{u}) = (\mathbf{u} \cdot \mathbf{v}) \cdot 0 = 0.\)3. \(\mathbf{u} \cdot (\mathbf{v} \times \mathbf{u}) = 0\) since \(\mathbf{u}\) is orthogonal to \(\mathbf{v} \times \mathbf{u}\).As all terms are zero, the total sum is zero.
05

Finishing Step: Conclusion

Since the dot product \( ((\mathbf{u} \cdot \mathbf{v})(\mathbf{u} + \mathbf{v}) + \mathbf{u}) \cdot (\mathbf{v} \times \mathbf{u}) = 0 \), this confirms that the vector \((\mathbf{u} \cdot \mathbf{v})(\mathbf{u}+\mathbf{v}) + \mathbf{u}\) is indeed orthogonal to \(\mathbf{v} \times \mathbf{u}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Orthogonality
Vector orthogonality is a fundamental concept in vector calculus that occurs when two vectors are perpendicular to each other. When vectors are orthogonal, their dot product equals zero. This condition is often used in various applications to check the perpendicularity of vectors.
For example, in the given exercise, you want to show that a vector expression is orthogonal to the cross product of two vectors. By taking the dot product of the vector expression with the cross product, you'll verify orthogonality because the dot product should equal zero.
Orthogonal vectors have important properties:
  • They define right angles between each other, which has applications in geometry and physics.
  • They maintain independence, meaning one cannot be represented as a scalar multiple of the other.
Recognizing when vectors are orthogonal helps in tasks like determining directions in three-dimensional space or in specific components of vector projections.
Dot Product
The dot product, also known as the scalar product, is an operation that takes two equal-length sequences of numbers (usually coordinate vectors), and returns a single number.
It is calculated as the product of the magnitudes of the vectors and the cosine of the angle between them. In formula terms, the dot product \( \mathbf{a} \cdot \mathbf{b} = |\mathbf{a}| |\mathbf{b}| \cos(\theta) \), where \( \theta \) is the angle between \( \mathbf{a} \) and \( \mathbf{b} \).
  • If the dot product is zero, the vectors are orthogonal.
  • The dot product is related to the projection of one vector onto another.
The dot product has practical applications in finding work done by a force or the angle between two vectors. In this exercise, each term in the expression \(((\mathbf{u} \cdot \mathbf{v})\mathbf{u} + (\mathbf{u} \cdot \mathbf{v})\mathbf{v} + \mathbf{u})\) is individually zero when dotted with \(\mathbf{v} \times \mathbf{u}\), confirming orthogonality.
Vector Calculus
Vector calculus is a branch of mathematics that deals with vector fields and operations on these fields. It extends the calculus concepts like differentiation and integration to vector spaces.
In vector calculus, you often deal with vector operations such as the dot product and cross product, each telling different things about the interactions between vectors.
  • The cross product gives a vector that is orthogonal to the original vectors, often used in physics to determine torque or angular momentum.
  • Operations like gradient, divergence, and curl in vector fields are crucial for understanding fluid dynamics and electromagnetism.

This field of study is powerful for solving real-world problems involving vector quantities. In this exercise, vector calculus allows you to explore properties, like orthogonality, and solve problems by manipulating and understanding the nature of vectors.

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Most popular questions from this chapter

For the following exercises, lines \(L_{1}\) and \(L_{2}\) are given. Determine whether the lines are equal, parallel but not equal, skew, or intersecting. \(L_{1} : x=-1+2 t, y=1+3 t, z=7 t, \quad t \in \mathbb{R}\) and \(L_{2} : x-1=\frac{2}{3}(y-4)=\frac{2}{7} z-2\)

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