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For the following exercises, the two-dimensional vectors a and \(\mathbf{b}\) are given. a. Find the measure of the angle \(\theta\) between a and b. Express the answer in radians rounded to two decimal places, if it is not possible to express it exactly. b. Is \(\theta\) an acute angle? $$ \mathbf{a}=\langle 2,1\rangle, \quad \mathbf{b}=\langle- 1,3\rangle $$

Short Answer

Expert verified
a. θ ≈ 1.35 radians. b. Yes, θ is an acute angle.

Step by step solution

01

Calculate the Dot Product

The dot product \( \mathbf{a} \cdot \mathbf{b} \) of two vectors \( \mathbf{a} = \langle 2, 1 \rangle \) and \( \mathbf{b} = \langle -1, 3 \rangle \) is computed as follows: \[ \mathbf{a} \cdot \mathbf{b} = (2)(-1) + (1)(3) = -2 + 3 = 1 \]
02

Calculate the Magnitude of Each Vector

First, find the magnitude of \( \mathbf{a} \), which is given by \[ \| \mathbf{a} \| = \sqrt{2^2 + 1^2} = \sqrt{4 + 1} = \sqrt{5} \]Next, find the magnitude of \( \mathbf{b} \), which is \[ \| \mathbf{b} \| = \sqrt{(-1)^2 + 3^2} = \sqrt{1 + 9} = \sqrt{10} \]
03

Calculate the Cosine of the Angle θ

The cosine of the angle \( \theta \) between \( \mathbf{a} \) and \( \mathbf{b} \) is given by the formula \[ \cos(\theta) = \frac{\mathbf{a} \cdot \mathbf{b}}{\| \mathbf{a} \|\| \mathbf{b} \|} = \frac{1}{\sqrt{5} \cdot \sqrt{10}} = \frac{1}{\sqrt{50}} = \frac{1}{5\sqrt{2}} \]
04

Calculate the Angle θ in Radians

To find \( \theta \), take the inverse cosine of \( \frac{1}{5\sqrt{2}} \): \[ \theta = \cos^{-1} \left( \frac{1}{5\sqrt{2}} \right) \]Using a calculator, this gives approximately \( \theta \approx 1.35 \) radians.
05

Determine if θ is an Acute Angle

An angle is acute if it is less than \( \frac{\pi}{2} \) radians (approximately 1.57 radians). Since \( \theta \approx 1.35 \) radians, \( \theta \) is an acute angle.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angle between Vectors
When dealing with vectors, understanding the angle between them is crucial for many applications such as physics and engineering. To find the angle between two vectors, we use the dot product formula.
The dot product of vectors \( \mathbf{a} \) and \( \mathbf{b} \) is defined as:
  • \( \mathbf{a} \cdot \mathbf{b} = a_1b_1 + a_2b_2 \) in two dimensions, where \( \mathbf{a} = \langle a_1, a_2 \rangle \) and \( \mathbf{b} = \langle b_1, b_2 \rangle \).
The cosine of the angle \( \theta \) between the vectors is calculated using:
  • \( \cos(\theta) = \frac{\mathbf{a} \cdot \mathbf{b}}{\| \mathbf{a} \| \| \mathbf{b} \|} \)
This equation tells us that the angle is determined by how the dot product relates to the magnitudes of the vectors. Finally, to find the angle, we calculate:
  • \( \theta = \cos^{-1} \left( \frac{\mathbf{a} \cdot \mathbf{b}}{\| \mathbf{a} \| \| \mathbf{b} \|} \right) \)
Using a calculator, you can find \( \theta \) in radians and determine the relationship between the vectors.
Magnitude of a Vector
The magnitude of a vector is essentially its length or size. It gives us an idea of how long the vector is from the origin to the point in space it represents. To calculate the magnitude in two dimensions, you can apply the Pythagorean theorem.
If you have a vector \( \mathbf{a} = \langle a_1, a_2 \rangle \), the magnitude \( \| \mathbf{a} \| \) is calculated as:
  • \( \| \mathbf{a} \| = \sqrt{a_1^2 + a_2^2} \)
This formula is an extension of the Pythagorean theorem. It squares each component of the vector, sums them, and then takes the square root.
Similarly, for vector \( \mathbf{b} = \langle b_1, b_2 \rangle \), the magnitude is:
  • \( \| \mathbf{b} \| = \sqrt{b_1^2 + b_2^2} \)
By understanding the magnitude of vectors, you can better analyze their characteristics, like speed in physics or size in graphical representations.
Acute Angle
An acute angle is one of the basic categorization of angles. It is defined as any angle that measures less than 90 degrees, or \( \frac{\pi}{2} \) radians.
In the context of vectors, determining if the angle between two vectors is acute can have significant implications. For example, in geometry, acute angles between vectors suggest that directions are more closely aligned rather than opposite.
To check if the angle \( \theta \) between two vectors \( \mathbf{a} \) and \( \mathbf{b} \) is acute, calculate \( \theta \) using the dot product and magnitudes as discussed before.
  • If \( \theta < \frac{\pi}{2} \), then the angle is acute.
  • This can help in understanding vector alignment or in optimizing directions for vector-based computations.
Recognizing acute angles aids in interpreting spatial relationships and optimizing the directionality in different fields of study.

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Most popular questions from this chapter

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