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For the following exercises, the vectors \(\mathbf{a}, \mathbf{b},\) and \(\mathbf{c}\) are given. Determine the vectors \((\mathbf{a} \cdot \mathbf{b}) \mathbf{c} \quad\) and \(\quad(\mathbf{a} \cdot \mathbf{c}) \mathbf{b}\) Express the vectors in component form. $$ \mathbf{a}=\mathbf{i}+\mathbf{j}, \quad \mathbf{b}=\mathbf{i}-\mathbf{k}, \quad \mathbf{c}=\mathbf{i}-2 \mathbf{k} $$

Short Answer

Expert verified
\((\mathbf{a} \cdot \mathbf{b}) \mathbf{c} = \mathbf{i} - 2\mathbf{k}\) and \((\mathbf{a} \cdot \mathbf{c}) \mathbf{b} = \mathbf{i} - \mathbf{k}\).

Step by step solution

01

Understand Dot Product and Vector Multiplication

The dot product of two vectors \(\mathbf{x}\) and \(\mathbf{y}\) is a scalar given by \(\mathbf{x} \cdot \mathbf{y} = x_1y_1 + x_2y_2 + x_3y_3\). For any vector \(\mathbf{z}\), the product \((\mathbf{x} \cdot \mathbf{y}) \mathbf{z}\) is a scalar multiplied by a vector, which scales the components of \(\mathbf{z}\) by this scalar.
02

Calculate the Dot Product \(\mathbf{a} \cdot \mathbf{b}\)

Given \(\mathbf{a} = \mathbf{i} + \mathbf{j}\) and \(\mathbf{b} = \mathbf{i} - \mathbf{k}\), calculate the dot product:\[\mathbf{a} \cdot \mathbf{b} = (1)(1) + (1)(0) + (0)(-1) = 1 + 0 + 0 = 1\]
03

Compute Vector \((\mathbf{a} \cdot \mathbf{b}) \mathbf{c}\)

Since \(\mathbf{a} \cdot \mathbf{b} = 1\) and \(\mathbf{c} = \mathbf{i} - 2 \mathbf{k}\), multiply by the scalar:\[1 \cdot \mathbf{c} = 1(\mathbf{i}) - 1(2 \mathbf{k}) = \mathbf{i} - 2 \mathbf{k}\]Thus, \((\mathbf{a} \cdot \mathbf{b}) \mathbf{c} = \mathbf{i} - 2 \mathbf{k}\).
04

Calculate the Dot Product \(\mathbf{a} \cdot \mathbf{c}\)

Given \(\mathbf{a} = \mathbf{i} + \mathbf{j}\) and \(\mathbf{c} = \mathbf{i} - 2 \mathbf{k}\), compute the dot product:\[\mathbf{a} \cdot \mathbf{c} = (1)(1) + (1)(0) + (0)(-2) = 1 + 0 + 0 = 1\]
05

Compute Vector \((\mathbf{a} \cdot \mathbf{c}) \mathbf{b}\)

Using \(\mathbf{a} \cdot \mathbf{c} = 1\) and \(\mathbf{b} = \mathbf{i} - \mathbf{k}\), multiply by the scalar:\[1 \cdot \mathbf{b} = 1(\mathbf{i}) - 1(\mathbf{k}) = \mathbf{i} - \mathbf{k}\]Thus, \((\mathbf{a} \cdot \mathbf{c}) \mathbf{b} = \mathbf{i} - \mathbf{k}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Multiplication
Vector multiplication is a fundamental concept in vector algebra. When people refer to vector multiplication, there are usually two types at play—dot product and cross product. In the current context, we are focusing on the dot product as it provides a scalar result.

The dot product (or scalar product) involves multiplying corresponding components of two vectors and then summing these products. For example, if you have vectors \( \mathbf{x} = x_1 \mathbf{i} + x_2 \mathbf{j} + x_3 \mathbf{k} \) and \( \mathbf{y} = y_1 \mathbf{i} + y_2 \mathbf{j} + y_3 \mathbf{k} \), the dot product is calculated as:
  • \( \mathbf{x} \cdot \mathbf{y} = x_1y_1 + x_2y_2 + x_3y_3 \)
This operation results in a scalar, not a vector, making it different from other forms of vector multiplication like the cross product.

Once the dot product is found, it can be used for further calculations, such as scalar multiplication with another vector, which we will delve into next.
Component Form
When expressing vectors, especially in calculations, it's often beneficial to use component form. Component form breaks a vector down into its constituent parts, described using unit vectors like \( \mathbf{i}, \mathbf{j}, \) and \( \mathbf{k} \).

For the vectors given in the exercise:
  • \( \mathbf{a} = \mathbf{i} + \mathbf{j} \)
  • \( \mathbf{b} = \mathbf{i} - \mathbf{k} \)
  • \( \mathbf{c} = \mathbf{i} - 2 \mathbf{k} \)
Each vector is expressed in terms of these unit vectors, where the coefficients represent the magnitudes along the \( x \), \( y \), and \( z \) axes, respectively.

Component form is particularly useful for performing operations like addition, subtraction, and especially the dot product, where you align and manipulate equivalent components. By using the component form, these calculations become straightforward and methodical.
Scalar Multiplication
Scalar multiplication involves scaling a vector by a scalar quantity. This operation won't change the direction of the vector, just its magnitude. Consider a vector \( \mathbf{v} = v_1 \mathbf{i} + v_2 \mathbf{j} + v_3 \mathbf{k} \) and a scalar \( k \).

Scalar multiplication affects each component of the vector like this:
  • \( k \cdot \mathbf{v} = k(v_1 \mathbf{i} + v_2 \mathbf{j} + v_3 \mathbf{k}) = kv_1 \mathbf{i} + kv_2 \mathbf{j} + kv_3 \mathbf{k} \)
This process is evident when multiplying the results of a dot product with another vector, as seen in the original exercise solution.

For example, after computing the dot product between vector \( \mathbf{a} \) and another vector, one can multiply this resultant scalar by a different vector (like \( \mathbf{c} \) or \( \mathbf{b} \)) to scale each of its components appropriately. This step is crucial for finding expressions like \((\mathbf{a} \cdot \mathbf{b}) \mathbf{c}\) and others, where a single number (scalar) adjusts the entire magnitude of a vector without altering its direction.

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