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When k2 is an integer, the polar graph of r=sinkorr=cosk is a rose. (a) How many petals does the rose have when k is an integer? (b) What can you say about the symmetries of eitherr=sinkorr=cosk when k is rational? Use a graphing calculator or a computer algebra system to graph several cases before answering the question. (c) What can you say about the polar graph ofrole="math" localid="1663157118656" r=sinkorr=coskwhen k is irrational?

Short Answer

Expert verified

(a). There are 2k and k number of rose petals when k is an even and odd integer.

(b). The graph is symmetric when k is an integer.

(c). The polar graph has infinite number of petals when k is irrational

Step by step solution

01

Given information

r=sinkorr=cosk

02

Part (a) Step 1: Number of rose petals when k is an integer. 

The graph of the given curves is,

It is observed that when k is even, there are 2k petals on the rose, and when k is odd, there are only k petals. This pattern emerges if k is any integer, including if k was negative.

03

Part (b) Step 1: Symmetry

For k=3the graph is,

When kis odd there will be k-1symmetry.

For k=6

When kis even there are ksymmetry

04

Graph when k is an irrational number.

When kis an irrational number, then the graph is as below

The graph for different irrational numbers:

There are infinite numbers of petals when k is an irrational numbers.

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