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91Ó°ÊÓ

In Exercises 83–86, use the given derivative f' to find any local extrema and inflection points of f and sketch a possible graph without first finding an formula for f .

f'x=exx+4

Short Answer

Expert verified

A critical point isx=-4

Step by step solution

01

Given information

The function's name isf'x=exx+4

02

Calculations

Consider the following factors while determining the important points:

f'x=0exx+4=0x+4=0x=4

As a result, A critical point is x=-4

Then take a look at the table below.

Interval(−∞,−4)
(−4,∞)
k-50
Value of the test for f'k
-+
sign of f'xf′(x)<0
f′(x)>0
ConclusionDecreasingIncreasing

Therefore, The crucial point isx=-4.

Then there's the graph of f,

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