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Let u,v, and wbe three mutually perpendicular vectors in 3.

(a) Prove that u(vw)=0.

(b) Show that |u(vw)|=uvw.

Short Answer

Expert verified

Ans:

part (a).

u(vw)=uwcos90v-uvcos90w=(0)v-(0)w=0

part (b)

.u(vw)=uvwcos=uvwcos0=uvw=uvwsin90=uvw

Step by step solution

01

Step 1. Given information:

There are three mutually perpendicular vectors in 3.

  • u(vw)=0
  • |u(vw)|=uvw
02

Step 2. Solving part (a):

The equation u(vw)=(uw)v-(uv)wgives:

u(vw)=uwcos90v-uvcos90w(Vectors are perpendicular)=(0)v-(0)w(Simplify)=0

Therefore, if three vectors are mutually perpendicular then u(vw)=0holds.

03

Step 3. Solving part (b).

The vectors uand vware parallel to each other.

The value of u(vw)is:

role="math" localid="1650748918202" u(vw)=uvwcos=uvwcos0(Angle betweenuandvw=uvw=uvwsin90(Because vectorsvandware perpendicular)=uvw

Therefore, the result u(vw)=uvw is proved.

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