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Find the equation of sphere with center (2, -3, 4), tangent to the xz-plane.

Short Answer

Expert verified

The required equation is:(x-2)2+(y+3)2+(z-4)2=9

Step by step solution

01

Given information

Given a sphere with center (2, -3, 4), tangent to the xz-plane.

02

Finding the equation

The radius of sphere will be equal to to the absolve value of y coordinate of the center as it is tangent to xz plane.

The radius is 3.

The required equation is:

(x-2)2+(y-(-3))2+(z-4)2=32

Simplify:

(x-2)2+(y+3)2+(z-4)2=9

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