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Chapter 10: Q 4 TB (page 788)

To find the equation of a circle in 鈩�2with center (3, 6) and is tangent to x- axis.

Short Answer

Expert verified

The required equation is(x-3)2+(y-6)2=36

Step by step solution

01

Given information

Given that the circle has center at (3, 6) and is tangent to x axis.

02

Finding the equation of circle

The circle is tangent to x axis, so radius is y coordinate of center.

The equation of circle is:

(x-3)2+(y-6)2=36

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Most popular questions from this chapter

Use calculator graphs to make approximations for each of the limits in Exercises 67鈥�74.

limx鈫�4(3-4x-5x2)

In Exercises 37鈥�42, find vand find the unit vector in the direction of v.

v=2,1,-5

If u, v and w are three vectors in 鈩�3, which of the following products make sense and which do not?

localid="1649346164463" (a)u路(v路w)(b)u路(v脳w)(c)u脳(v路w)(d)u脳(v脳w)

Find PQ鈫�

P=-1,5,4,Q=-1,6,4

Use the definition of the derivative to find f'for each function fin Exercises 39-54

f(x)=12x+1
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