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In Exercises 32–36,

(a) computeu.v

(b) find the angle between u and v, and

(c) findprojuv

Short Answer

Expert verified

Part a)u.v=37

Part b) angle is θ=cos-1371378

Part c)The value ofprojuvis3726⟨1,5⟩.

Step by step solution

01

Step 1:Given information Part a)

u and v are vectors

02

Part a) Simplification

Consider the vectoru=⟨1,5⟩,v=⟨2,7⟩.

Ifuandvare the vector such thatu=u1,v1andv=u2,v2, then dot product is given by

u.v=u1v1+u2v2.

u·v=1(2)+5(7)

=37

03

Step 3:Part b) Given information

u,vare given vectors

04

Step 4:Part b)Simplification

u.v=37

Also,u=⟨1,5⟩

Therefore

‖u‖=12+52

=26

Also,v=⟨2,7⟩

‖v‖=22+72

=53

now,

cosθ=372653

⇒θ=cos-1371378

Hence, the angle between the vectors is cos-1371378

05

Part c):Given information

the vectoru=⟨1,5⟩,v=⟨2,7⟩

06

Step 6:Part c) Simplification

⇒u.v=37calculated

and

‖u‖=26

Letube any non- zero vector, then the vector projection ofvontouis given by

projuv=u·v‖u‖2u·Now, substitute the values inprojuv=u·v‖u‖2u

projuv=37(26)2⟨1,5⟩

=3726⟨1,5⟩

Hence, the value ofprojuvis3726⟨1,5⟩.

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