/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 25 In Exercises 22鈥29 compute the... [FREE SOLUTION] | 91影视

91影视

In Exercises 22鈥29 compute the indicated quantities when u=(2,1,3),v=(4,0,1),andw=(2,6,5)

role="math" localid="1649400253452" (uv)wandu(vw)

Short Answer

Expert verified

The value of(uv)w=94i-3j+34kandu(vw)=90i-30j+50k.

Step by step solution

01

Step 1. Given Information 

In Exercises 22鈥29 compute the indicated quantities whenu=(2,1,3),v=(4,0,1),andw=(2,6,5)

We have to find the value of(uv)wandu(vw)

02

Step 2. Firstly finding the value of (u×v)×w

The cross product of uv=detijk21-3401

Now solving the cross product.

uv=((1)(1)(3)(0))i+((2)(1)(-3)(4))j+((2)(0)(1)(4))kuv=(1-0)i+(2+12)j+(04)kuv=1i+14j-4k

03

Step 3. Now the vectors of u×v is (1,14,-4).

Now finding the value of (uv)w

role="math" localid="1649401901776" (uv)w=detijk114-4-265(uv)w=((14)(5)(4)(6))i+((1)(5)(-4)(-2))j+((1)(6)(14)(-2))k(uv)w=(70+24)i+(5-8)j+(6+28)k(uv)w=94i-3j+34k

04

Step 4. Firstly finding the value of v×w

The cross product of vw=detijk401-265

vw=((0)(5)(1)(6))i+((4)(5)(1)(-2))j+((4)(6)(0)(-2))kvw=(0-6)i+(20+2)j+(24+0)kvw=-6i+22j+24k

05

Step 5. Now the vectors of v×w is (-6,22,24)

u(vw)=detijk21-3-62224u(vw)=((1)(24)(3)(22))i+((2)(24)(-3)(-6))j+((2)(22)(1)(-6))ku(vw)=(24+66)i+(48-18)j+(44+6)ku(vw)=90i-30j+50k

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.