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In Exercises 22–29 compute the indicated quantities when u=(2,1,−3),v=(4,0,1),andw=(−2,6,5)

u×wandw×u

Short Answer

Expert verified

The value ofu×w=23i+4j+14kandw×u=-23i-4j-14k.

Step by step solution

01

Step 1. Given Information 

In Exercises 22–29 compute the indicated quantities whenu=(2,1,−3),v=(4,0,1),andw=(−2,6,5)

We have to find the value of u×wandw×u

02

Step 2. Firstly finding the value of u×w

The value of vectorsu=(2,1,−3),w=(−2,6,5)

The cross product ofu×w=detijk21-3-265

03

Step 3. Now solving the matrix. 

u×w=detijk21-3-265u×w=((1)(5)−(−3)(6))i+((2)(5)−(-2)(-3))j+((2)(6)−(1)(-2))ku×w=(5+18)i+(10−6)j+(12+2)ku×w=23i+4j+14k

04

Step 4. Firstly finding the value of w×u

The value of vectorsw=(−2,6,5)andu=(2,1,−3)

The cross product ofw×u=detijk-26521-3

05

Step 5. Now solving the matrix. 

w×u=detijk-26521-3w×u=((6)(-3)−(5)(1))i+((-2)(-3)−(5)(2))j+((-2)(1)−(6)(2))kw×u=(-18-5)i+(6−10)j+(-2-12)kw×u=-23i-4j-14k

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