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In Exercises 22鈥29 compute the indicated quantities when u=(2,1,3),v=(4,0,1),andw=(2,6,5)

uvandvu

Short Answer

Expert verified

The value of uv=1i+14j-4kandlocalid="1649397999598" vu=-1i-14j+4k

Step by step solution

01

Step 1. Given Information 

In Exercises 22鈥29 compute the indicated quantities whenu=(2,1,3),v=(4,0,1),andw=(2,6,5)

We have to find the value ofuvandvu

02

Step 2. Firstly finding the value of u×v

The value of vectors u=(2,1,3),v=(4,0,1)

The cross product of uv

localid="1649398046712" uv=detijk21-3401

03

Step 3. Now solving the matrix.

uv=detijk21-3401uv=((1)(1)(-3)(0))i+((2)(1)(-3)(4))j+((2)(0)(1)(4))kuv=(1+0)i+(2+12)j+(04)kuv=1i+14j-4k

04

Step 4. Now finding the value of v×u

The value of vectorsu=(2,1,3),v=(4,0,1)

The cross product ofvu=detijk40121-3

05

Step 5. Now solving the matrix. 

vu=detijk40121-3vu=((0)(-3)(1)(1))i+((4)(-3)(1)(2))j+((4)(1)(0)(2))kvu=(0-1)i+(-12-2)j+(40)kvu=-1i-14j+4k

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