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Let P0 be a point on a curve C with positive curvature 魏. Define the radius of curvature at P0

Short Answer

Expert verified

=1+222

Step by step solution

01

Step 1. Given information.

Given:

P0be a point on a curve C with positive curvature 魏

We have to define the radius of curvature atP0.

02

Step 2. Curvature

Let r(t)=t,sint,costand t=0

r(t)=t,sint,cost

at t=0,r(0)=0,0,

Differentiate r(t) with respect to t,

r(t)=1,cost,sint

and,

localid="1649998970850" r(t)=1+cost2+(sint)2=1+22

Now,

localid="1649999060548" T(t)=r(t)r(t)=1,cost,sint1+22T(t)=11+220,2sint,2costT(t)=0+24sin2t1+22+24cos2t1+22=24sin2t+cos2t1+22=21+22sincesin2t+cos2t=1

Since, r(t)=1+22then to have r(0)=1+22

Since, T(t)=21+2which is a constant.

Then,

T(0)=21+2

03

Step 3. The radius of the curvature

The curvature k of c at a point on the curve is given by :

k=T(0)r(0)

localid="1649999096384" =21+221+22=21+22

Therefore, the radius of the curvature is :

localid="1649999122418" =1k=1+222

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