/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 58 Let r1(t) and r2(t) be contin... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Let r1(t)andr2(t)be continuous vector functions with three components, and let t0be a point in the domains of both r1andr2. Prove that

localid="1649617482201" limt→t0 r1(t)×r2(t)=r1t0×r2t0

Short Answer

Expert verified

Ans: It is proved thatlimt→t0 r1(t)×r2(t)=r1t0×r2t0

Step by step solution

01

Step 1. Given information. 

given,

limt→t0 r1(t)×r2(t)=r1t0×r2t0

02

Step 2. Solution

Consider two continuous vector functions with three components. Let

r1(t)=x1(t),y1(t),z1(t)andr2(t)=x2(t),y2(t),z2(t)

The objective is to prove that

limt→t0 r1(t)×r2(t)=r1t0×r2t0where t0belongs to the domains of r1andr2.

Since role="math" localid="1649617811675" r1(t)andr2(t)are continuous, their components x1(t),y1(t),z1(t),x2(t),y2(t),z2(t)are continuous. Thus product and sum of the continuous functions are also continuous.

Therefore,r1(t)×r2(t)is continuous.

03

Step 3. Consider

limt→t0 r1(t)×r2(t)=limt→t0 y1(t)z2(t)−y2(t)z1(t),x2(t)z1(t)−x1(t)z2(t),x1(t)y2(t)−x2(t)y1(t)=limt→t0 y1(t)z2(t)−y2(t)z1(t)i+limt→t0 x2(t)z1(t)−x1(t)z2(t)j+limt→r0 x1(t)y2(t)−x2(t)y1(t)k

From the definition of a continuous function.

=y1t0z2t0−y2t0z1t0i+x2t0z1t0z1t0−x1t0z2t0j+limt→t0 x1t0y2t0−x2t0y1t0k=y1t0z2t0−y2t0z1t0,x2t0z1t0−x1t0z2t0x1t0y2t0−x2t0y1t0=r1t0×r2t0

Thus,limt→t0 r1(t)×r2(t)=r1t0×r2t0

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.