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Find the given limits if they exist. If a limit does not exist, explain why.

limt→013+t-13t,3+t2-9t.

Short Answer

Expert verified

The limit exists. The solution is,

-13,6.

Step by step solution

01

Step 1. Given Information.

The limit is,

limt→013+t-13t,3+t2-9t.

02

Step 2. Whether the limit exists or not.

Consider the limit,

limt→013+t-13t,3+t2-9t

The objective is to evaluate the above limit.

limt→t0r(t)=limt→t0(x(t),y(t),z(t))=(limt→t0x(t),limt→t0y(t),limt→t0z(t))

Here, limt→t0x(t),limt→t0y(t),and limt→t0z(t)exist.

03

Step 3. Finding the limit.

limt→01t13+t-13,3+t2-9t=limt→01t3-3-t(3+t),9+t2+6t-9t=limt→01t-t3+t,t2+6tt=limt→0-13+t,t+6=limt→0-13+t,limt→0t+6=-13,6

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