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Give an intuitive explanation of why the surface of a tetrahedron is piecewise smooth but the surface of the conez=x2+y2 is not.

Short Answer

Expert verified

The pyramid surface Swith vertices is,(0,0,6),(2,0,0),(2,0,0),(0,3,0),(0,3,0).

The surface localid="1650812482668" Sis not smooth or piece-wise smooth surface so, the Stoke's theorem does not applies.

Step by step solution

01

Step: 1 Stoke's theorem:

By Stoke's theorem,

Stokes states, "One must be an aligning, homogenous, or linear field bound by a curve C." Assume that nis an aligned unitary paralleled line of Sand that Cis placed in institutions in the opposite direction ofn.

If Fis a vector field defined on Sis,

CF(x,y,z)dr=ScurlF(x,y,z)ndS"

02

Step: 2 Stokes' Theorem hypothesis:

As a result, Stokes' Theorem has the following hypothesis:

(1)The parameter Fis specified and indefinitely non - linear on an open set including the surface Sconstrained by localid="1650813223754" C.

(2)Curve Cis a simple, smooth, and closed border curve.

(3) The area S is smooth and aligned.

03

Step: 3 Surace of cone:

The following surface are,

The pyramid surface Swith vertices is,

(0,0,6),(2,0,0),(2,0,0),(0,3,0),(0,3,0).

The surface Sis not smooth or piece-wise smooth surface so, the Stoke's theorem does not applies.

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