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In Exercises 17–24, find a potential function for the given vector field.

G(x,y,z)=(yexy+z,xexy+z,exy+z)

Short Answer

Expert verified

A potential function for the given vector field is g(x,y,z)=exy+z.

Step by step solution

01

Step 1. Given Information

In given exercises we have to find a potential function for the given vector field.

G(x,y,z)=(yexy+z,xexy+z,exy+z)

02

Step 2. Since G(x,y,z)=(yexy+z, xexy+z, exy+z)

g(x,y,z)=∫yexy+zdx+B+Cg(x,y,z)=∫yexy·ezdx+B+CLetu=xydudx=ydu=ydxg(x,y,z)=ez∫eudx+B+Cg(x,y,z)=ezeu+α+B+Cg(x,y,z)=ezexy+α+B+Cg(x,y,z)=exy+z+α+B+C

where α is an arbitrary constant and B is the integral with respect to y of the terms in localid="1650474562962" G2(x,y,z) in which the factor x does not appear.

03

Step 3. In this case, that is all of G2(x,y,z), so

B=∫xexy+zdyB=∫xexy·ezdyLetu=xydudy=xdu=xdyB=ez∫eudyB=ezeu+βB=ezexy+βB=exy+z+β

whereβ is an arbitrary constant.

04

Step 4. Now finding C=∫exy+zdz

C=∫exy·ezdzC=exy∫ezdzC=exyez+γC=exy+z+γ

whereγ is an arbitrary constant.

Setting the constants equal to zero since they do not affect the gradient of g(x,y,z)

We have,

g(x,y,z)=exy+z

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