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∬SF(x,y,z)·ndswhere Sis the portion of the hyperboloid of two sheets x2+y2+1=z2that lies between the planes z=5and z=10and whereF(x,y,z)=x2-2y+z2,4x+z-2,2xyz

Short Answer

Expert verified

The integral ∬SF(x,y,z)·nds, can be evaluated by means of Divergence Theorem.

Step by step solution

01

Introduction

Consider the vector field below:

F(x,y,z)=x2-2y+z2,4x+z-2,2xyzThe goal is to determine whether the integral ∬SF(x,y,z)·ndscan be evaluated using the Divergence Theorem, with the surface $S$ being the section of the hyperboloid of two sheets x2+y2+1=z2lying between the planes z=5andz=10.

Divergence According to the theorem,

"Let Wbe a bounded region in R3with a smooth or piecewise-smooth closed oriented surface as its boundary S. If on an open region containing W, a vector field F(x,y,z)is defined, then

∬SF(x,y,z)·ndS=∭WdivF(x,y,z)dV."........(1)

where n is the outwards unit normal vector. "

02

Explaination

The piecewise-smooth surface Sis the section of the hyperboloid of two sheets x2+y2+1=z2that falls between the planes z=5and z=10. Also defined in the region enclosed by Sis the vector field F(x,y,z)=x2-2y+z2,4x+z-2,2xyz

Divergence Only smooth or piecewise-smooth surfaces with a vector field F(x,y,z)defined on the region encompassed by Scan be used to prove the theorem.

Yes, the integral ∬SF(x,y,z)·nds, can be evaluated by means of Divergence Theorem.

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