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Give an example of a conservative vector field whose divergence is uniformly equal to zero in3.

Short Answer

Expert verified

An example of a conservative vector field whose divergence is uniformly equal to zero in

3is F(x,y,z)=i+j+k

Step by step solution

01

Introduction

The goal is to demonstrate a conservative vector field whose divergence is uniformly equal to zero in all directions.3

If Fxy,y,zis a conservative vector field, then.

F(x,y,z)=Vf(x,y,z)

02

:

The divergence of a vector field F(x,y,z)=F1(x,y,z)i+F2(x,y,z)j+F3(x,y,z)kis defined as follows divF=.F

Then the divergence of conservative vector fieldF(x,y,z)=f(x,y,z)will be,

divF=.F

=.f=(xi+yj+zk).(fxi+fyj+fzk)=x(fx)+y(fy)+z(fz)=2fx2+2fy2+2fz2

03

:

Hence, a conservative vector field whose divergence is uniformly equal to zero in 3satisfies the following conditions,

2fx2=0,2fy2=0,2fz2=0

Suppose that , f=x+y+z, then

f=(xi+yj+zk)(x+y+z)=x(x+y+z)i+y(x+y+z)j+z(x+y+z)k=1i+1j+1k=i+j+k

Then, the vector field F(x,y,z)=i+j+kis a conservative vector field, such that F=f

Where F=x+y+z

Notice that,

2fx2=2x2(x+y+z)=x(x(x+y+z))=x(1)=02fy2==2y2(x+y+z)=y(y(x+y+z))=y(1)=02fz2=2z2(x+y+z)=z(z(x+y+z))=z(1)=0

Hence, the divergence for this conservative vector field F(x,y,z)=i+j+k is uniformly equal to zero in .

Therefore, an example of a conservative vector field whose divergence is uniformly equal to zero in 3is

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